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Hello.
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In problem number 13, we're looking at an elevator that will be accelerated upward by connecting it to a counterweight over a uniform cylindrical pulley.
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So let's take a look at the numbers we have right now.
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We know that this is the elevator and it is got a 22 ,500 newton weight.
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And we don't know the size of our counterweight.
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The pulley has a diameter of 1 .5, which gives us then a radius here of 0 .75.
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We know the mass of that pulley, 875 kilograms.
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So first question i ask this is what is the size of this counterweight.
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And we also need to know what's the tension in both sides on the rope on both sides.
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Now, we get us a little help here in that they tell us that the elevator will be accelerating upward, a distance of 6 .75.
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So the distance that this elevator will be moving is 6 .75 meters.
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And it does that in three seconds.
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We know also that it's the velocity initial is zero.
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So that helps us a little bit there.
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And gives us a few things to help us.
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First, we can use this information to find, our acceleration of our elevator.
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I'm going to do this on the other page here.
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So we know using our kinematics formulas that we can find the acceleration.
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We were given this displacement of this elevator is 6 .75.
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We know it started from rest, and that occurred in three seconds.
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Solving 4a, we get an acceleration of 1.
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1 .5 meters per second squared.
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So that helps us out.
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And remember it's going up, which means this counterweight would be coming down.
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Now, we need to look at kind of the three separate things going on here.
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First, i'm going to look at the elevator itself from a three -body standpoint.
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We know it has a downward weight of 22 ,500 newtons.
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And we have enough for tension.
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And i'm going to call this tension the left tension.
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Now, looking at the counterweight, similar, free body.
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We just don't know what that weight is, but we know this, and i'm going to call this the right tension.
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Now, we do have some torque on our pulley system here that we will want to look at.
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We know that there is a torque that's going to rotate this pulley clockwise, and that is due to the tension in the right cable.
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And then we also have the tension in the left cable that's going to do a counterclockwise rotation.
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Calculate here, because we will need to know our moment of inertia.
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Moment of inertia for a cylinder.
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So our moment of inertia of this cylinder is one -half mr -squared.
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In this case, it's one -half.
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Our mass is 875 times diameter squared.
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This actually is 246 kilogrammeater square.
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Okay...