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\bullet A 60.0 -cm, uniform, $50.0-\mathrm{N}$ shelf is supported horizontally by two vertical wires attached to the sloping ceiling (Fig. $10.59 ) .$ A very small $25.0-\mathrm{N}$ tool is placed on the shelf midway between the points where the wires are attached to it. Find the tension in each wire. Begin by making a free-body diagram of the shelf.

25 $\mathrm{N}$

Physics 101 Mechanics

Chapter 10

Dynamics of Rotational Motion

Newton's Laws of Motion

Rotation of Rigid Bodies

Equilibrium and Elasticity

University of Michigan - Ann Arbor

University of Washington

University of Sheffield

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Hello, Problem Number 41 talks about a 50 Newton uniforms shelf that's being supported by two wires. I'm gonna call the tension in this wire here the left tension in this the right tension. Our boards 0.6 meters long. The wires are 0.4 meters apart and it is a 50 new uniform chill. Those are placed a 25 noon tool halfway between you two wires. Our question is, what are the tensions in the two wires? We'll be looking at it from two points, will be looking at the network's being zero because that's what this shellfish stationery and not pivoting and we will also be looking at. The force is in the wind direction. We know those are in equilibrium, so the left in the right wire have to support the two weights. So we're looking about pivot point of the left wire. We know that the left wire has a level. Men of zero does not provide any tour, but they're what right wire as a lever arm. A 0.6 in provides a counterclockwise tour. Those that would be equal to the 25 minute tool with a lever arm, a point too and 50 need on board with a lever arm of 500.3 solving. Then for a right tension, we get 50 Newtons. I'm looking at our net. Force is in the one direction. We know that the left and the right wire must support 25 Newton Tool in the 15 Newton board. Already having calculated for the 50 Newton right wire, we solved and can see that the left wire as a 25 new intention. Thank you for learning with me.

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