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$\bullet$ A 7300 $\mathrm{N}$ elevator is to be given an acceleration of 0.150 $\mathrm{g}$by connecting it to a cable of negligible weight wrapped around a turning cylindrical shaft. If the shaft's diameter can be no larger than 16.0 $\mathrm{cm}$ due to space limitations, what must be its minimum angular acceleration to provide the required acceleration of the elevator?

18.4 $\mathrm{rad} / \mathrm{s}^{2}$

Physics 101 Mechanics

Chapter 9

Rotational Motion

Physics Basics

Rotation of Rigid Bodies

Dynamics of Rotational Motion

Equilibrium and Elasticity

Cornell University

Hope College

University of Winnipeg

McMaster University

Lectures

04:16

In mathematics, a proof is a sequence of statements given to explain how a conclusion is derived from premises known or assumed to be true. The proof attempts to demonstrate that the conclusion is a logical consequence of the premises, and is one of the most important goals of mathematics.

02:21

In physics, rotational dynamics is the study of the kinematics and kinetics of rotational motion, the motion of rigid bodies, and the about axes of the body. It can be divided into the study of torque and the study of angular velocity.

02:47

(II) An elevator (mass 485…

01:59

An old-style elevator is c…

01:33

An elevator (mass $4850 \…

10:25

(III) A steel cable is to …

02:38

03:27

In a charming 19th-century…

04:57

03:00

The cable lifting an eleva…

01:01

(II) A 12.0-kg monkey hang…

11:26

\bullet A $22,500$ N eleva…

01:28

(II) A 13.0 -kg monkey han…

03:15

In a charming 19 th centur…

01:45

A cord is wrapped around t…

02:40

(II) A 17.0 -kg monkey han…

02:50

A frictionless pulley, whi…

01:11

Utracentrifuge. Find the r…

in this problem, we are going to help let the England expression, which we call Alpha the angler expression, is related to the linear exploration through the question equals to our alpha. Here is the linear exploration. I was holding this equation for Alpha. We have all cycles to Eddie wanted by us now setting the Williams into this equation. We will get if I equals two 0.150 meter in tow. Mind pointed. Zero meters per second squared, divided by 0.800 meter. So this review us, I'll fight equals two at in point for radiant parts can square. So this is our answer.

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