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$\bullet$ A blue puck with mass 0.0400 $\mathrm{kg}$ , sliding with a velocityof magnitude 0.200 $\mathrm{m} / \mathrm{s}$ on a frictionless, horizontal air table,makes a perfectly elastic, head-on collision with a red puckwith mass $m,$ initially at rest. After the collision, the velocity of the blue puck is 0.050 $\mathrm{m} / \mathrm{s}$ in the same direction as its initialvelocity. Find (a) the velocity (magnitude and direction) of thered puck after the collision; and (b) the mass $m$ of the red puck.

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(a) $v_{B 2}=0.250 \mathrm{m} / \mathrm{s}$ in the same direction of the blue puck(b) $m=0.0240 \mathrm{kg}$

Physics 101 Mechanics

Chapter 8

Momentum

Physics Basics

Kinetic Energy

Potential Energy

Energy Conservation

Moment, Impulse, and Collisions

University of Washington

Simon Fraser University

Hope College

University of Winnipeg

Lectures

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In physics, mechanical energy is the sum of the kinetic and potential energies of a system.

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In physics, a conservative force is a force that is path-independent, meaning that the total work done along any path in the field is the same. In other words, the work is independent of the path taken. The only force considered in classical physics to be conservative is gravitation.

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A blue puck with mass 0.04…

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On a frictionless. horizun…

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$\bullet$ On a frictionles…

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Hockey puck $B$ rests on a…

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A $0.300-\mathrm{kg}$ puck…

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A 0.300 -kg puck, initiall…

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(II) A 0.450-kg hockey puc…

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(II) A $0.450-\mathrm{kg}$…

in this case we have a red buck, Let's say off mass M and it is stationary initially and then we have a blue book morning with velocity zero point 0400 meters per second. I'm sorry. They're a 0.200 meter per second and has a mass of 0.400 kilograms. That is 40 grands now. After the collision, the blue Book is moving in the same direction with the velocity zero point 05 meter per second. We want to find out the velocity off the right buck. Let's say after the collision the red packets moan with velocity. We know we know that in a perfectly elastic collision which disease we be f minus. B A is minus. We be I minus B A. They've lost the related velocity off approach has the same attitude as related velocity of separation. So for the but the second object, the final velocity is the And for the first object, the final velocity is 0.5 I'm for the second object, the initial velocity zero. And for this first object, the initial velocity Is there a point to which gives us We is equal to 0.25 major for second. Now that we know, this here comes to us like a trickier part. Find the mass off the grade book now in your books in the equation. Ate one point to you can see that we be f He's to m a bye, a less M b b a I This is the case for when a moving object hits a stationary object. This is the formula for the final velocity off the second object. No, because we know the final velocities syrup onto five feet per second. So we know this and you know the initial velocity off the moving object, which is their upon two meter per second. And we know the mass of A. We simply need to find Master P by sending this expression over here on V B f or here we see m A. It's empty bye to Emmy is wi I I by V b f. Now, by splitting this into fractions, we can see that. See that it is if you send this to hear first, Maybe I am a simply one less empty by EMI is equal to to be a I Bye, baby f By rearranging this, we can see M b is equal to to me I by v b f minus one. So we send the 4th 1 here first and then multiply by EMI on both sides. We know that the eye is your point. So simply and bees two times b I is 0.2 v b f Is there a 0.25 minus one times Amy which is 0.4 kilograms. This gives us that envy is little point 0240 kilograms.

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