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Problem 10 Medium Difficulty

$\bullet$ A circular loop of wire with a radius of 12.0 $\mathrm{cm}$ is lying flat on a tabletop. A magnetic field of 1.5 $\mathrm{T}$ is directed vertically upward through the loop (Figure 21.49 ). (a) If the loop is removed from the field region in a time interval of 2.0 $\mathrm{ms}$ , find the average emf that will be induced in the wire loop during the extraction process. (b) If the loop is viewed looking down on it from above, is the induced current in the loop clockwise or counterclockwise?

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Nathalie F.

October 20, 2020

missing pie in the equation

Nathalie F.

October 20, 2020

how is the answer for part a 34V when on my calculator i get 10.8?

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Christina Krawiec

Rutgers, The State University of New Jersey

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So some givens we have a fair day's law in this states that thie induced EMF is equaling too is equal to the absolute value of thie. Change of the magnetic flux with respect to time, we also know that the magnetic flux is going to be equal to the magnitude of the magnetic field times the area times co sign If I we know coast kind of flies going to be equal toe one in this case s O, we can say that the induced IMF will be equal to the negative B times A by the by Delta T or we can simply say be a overdone titty. So at this point for party, they want us to find the IMF. So this is going to be equal. Teo 1.5 Tesla's times 0.120 meters squared, and then this will be divided by time. In this case, no, what's 2.0 times 10 to the negative third seconds and we find that the induced EMF here is going to be approximately 34 volts. So this would be your answer for a party? Um, for part B, we're going to use lenses law and lenses. Law states that the direction of an induced current opposes the change in the circuit or the magnetic field that produced the current. So here, we're going to use right hand rule again. Your thumb represents the magnetic field, and you're curled. Fingers will represent the direction of the current. So here again, the induced current will follow right hand rule. So if we looking at top of coil, we can say that the magnetic field is out of the page. So in this case, this means that the direction ah, see, induced current is counterclockwise again. This is according to right hand rule. So this would be your answer for part B. That is the end of the solution. Thank you for watching.

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Hugh D. Young

College Physics

Christina Krawiec

Liev Birman

Marshall Styczinski

Jared Enns

This textbook answer is only visible when subscribed! Please subscribe to view the answer

College Physics

Christina Krawiec

Liev Birman

Marshall Styczinski

Jared Enns

Hugh D. YoungCollege Physics

Christina Krawiec

Liev Birman

Marshall Styczinski

Jared Enns

Hugh D. Young

College Physics