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\bullet A freezer has a coefficient of performance of 2.40 . Thefreezer is to convert 1.80 $\mathrm{kg}$ of water at $25.0^{\circ} \mathrm{C}$ to 1.80 $\mathrm{kg}$ ofice at $-5.0^{\circ} \mathrm{C}$ in 1 hour. (a) What amount of heat must beremoved from the water at $25.0^{\circ} \mathrm{C}$ to convert it to ice at $-5.0^{\circ} \mathrm{C} ?$ (b) How much electrical energy is consumed by thefreezer during this hour? c) How much wasted heat is rejectedto the room in which the freezer sits?

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(a) The heat removed equals $-808 \mathrm{kJ}$(b) The electrical energy consumed equal 337 $\mathrm{kJ}$(c) The wasted heat equal 1145 $\mathrm{kJ}$

Physics 101 Mechanics

Chapter 16

The Second Law of Thermodynamics

Temperature and Heat

Thermal Properties of Matter

The First Law of Thermodynamics

Cornell University

Hope College

McMaster University

Lectures

03:15

In physics, the second law of thermodynamics states that the total entropy of an isolated system can only increase over time. The total entropy of a system can never decrease, and the entropy of a system approaches a constant value as the temperature approaches zero.

03:25

The First Law of Thermodynamics is an expression of the principle of conservation of energy. The law states that the change in the internal energy of a closed system is equal to the amount of heat energy added to the system, minus the work done by the system on its surroundings. The total energy of a system can be subdivided and classified in various ways.

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A freezer has a coefficien…

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\bullet A freezer has a co…

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20.12. A freezer has a coe…

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A freezer with a coefficie…

04:01

$\bullet$ A Carnot freezer…

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An ice-making machine oper…

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To make some ice, a freeze…

told her freezer has a coefficient of performance of 2.4. The freezer is to confer 1.8 kilograms of water at 25 C to 1.8 kilograms of ice at minus five C in one hour. What amount of heat must be removed from the water to convert it to ice? Okay, so you have our givens and we know the latent heat effusion for changing water into ice. It's 3.34 times 10 to the fifth Jules per kilogram, so we can figure out what the the change in internal energy off the material is off the water with fluid. So it is the amount of energy needed to take the liquid water to solid water, so the water to ice. So that's the mass of the water, which is also the mass of the ice times. Latent heat, effusion and then we also have minus the mass of the water times the heat capacity of water times, its temperature minus its zero temperature and then minus the mass of the water, which is also the mass of the ice times the capacity of ice time zero minus its temperature. And if we plug everything in. Well, first, we can pull out a the mass of the water. So we get minus the mass of the water. Times quantity late here. Fusion, plus the key capacity ofwater times the temperature of the water. Remind us the capacity vice times the temperature of the ice. And if we start plugging numbers, we get that that is minus 808 killer tools. Now, we also know that there's no work done by the water on the water. So the the heat eggs orbit the heat of door from the water is changing internal energy. So that is minus eight and a killer. Jules. Now we know the performance. Um, the coefficient of performance is the absolute value of the he absorbed from the water provided by the work in. So we can find that the work in is the heat absorbed from the water. The absolute value that provided by the coefficient performance with 2.4 and we get 337 till it. Jules. Now the heat the heat absorbed he dumped to the, um with the waste heat rejected to the room is done just the they work. Yeah, work that is minus the heat absorbed by the ice. And that winds up being £1100 45 killing tools.

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