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$\bullet$ A gas under a constant pressure of $1.50 \times 10^{5} \mathrm{Pa}$ and with an initial volume of 0.0900 $\mathrm{m}^{3}$ is cooled until its volume becomes 0.0600 $\mathrm{m}^{3} .$ (a) Draw a $p V$ diagram of this process. (b) Calculate the work done by the gas.

$-4500 J$

Physics 101 Mechanics

Chapter 15

Thermal Properties of Matter

Temperature and Heat

The First Law of Thermodynamics

The Second Law of Thermodynamics

Rutgers, The State University of New Jersey

University of Washington

Simon Fraser University

University of Winnipeg

Lectures

03:15

In physics, the second law of thermodynamics states that the total entropy of an isolated system can only increase over time. The total entropy of a system can never decrease, and the entropy of a system approaches a constant value as the temperature approaches zero.

03:25

The First Law of Thermodynamics is an expression of the principle of conservation of energy. The law states that the change in the internal energy of a closed system is equal to the amount of heat energy added to the system, minus the work done by the system on its surroundings. The total energy of a system can be subdivided and classified in various ways.

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An ideal gas expands at a …

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Pisces, Chapter 15. Problem number 38 We have a guest under constant pressure of 1.5 temp stems with four of five plus fours at Constant. Well, this is a constant pressure, right? So the volume all this gas is changing. However, from an initial value Our 0.9 meter cute to a 0.6 meter cube. So the volume of this gas is decreasing, right? So in part, they were asked to draw the TV diagram for this process. So in the PV diagram, you're why access is the pressure and X axis would be the volume since the wall he was changing. So porno now and will be here. So this is the initial volume and then point. No, let's say, uh, 0.0.6 is somewhere here. So pressure is constant the whole time, right? So it is a straight line. It corresponds to 1.5 here. So then initial case and the final kids. So this is how you could draw the PV diagram for this process. Now, in heartbeat arrest, a calculator work done is another worked out in terms of pressure is P delta V to change in the walled in times. The pressure fresh is 1.5 times center for five. Paschal's and change in volume would be the final minus V initial final being point of six initial being for No. Nine meter cubed. So overall we find the work done to be negative 4500 jewels. So this negative means well, the volume is decreasing, right?

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