00:01
Hey everyone, this is question number 10 from chapter 14.
00:04
This problem is about train tracks being laid, and we're given an initial length that they're laid in 12 meter sections, an initial temperature, negative 2 degrees c, and then for part a, space needed between if they are just to touch at 33 degrees celsius, and b, if in contact, when laid, what is the stress in the tracks at 33 degrees c? so for part a, we have initial length, we have initial temperature, we're given a final temperature, and we need how much length between them, so we essentially need a delta l.
00:41
So we should be thinking thermal expansion, which we're given equation in the book, delta l equals l -not alpha delta t.
00:53
So we're given all these things, we're given an l -0, we can find an alpha, and we're given a delta t.
00:59
So we can just plug these in and solve for the delta l which would be the space that is needed.
01:11
So 12 meters, which is our l0.
01:16
Our alpha for steel is 1 .2 times 10 to the minus 5.
01:27
And then our change in temperature is 33 minus negative 2, which ends up being 35.
01:36
And if you plug that in, you get a delta l of 5 millimeters...