Download the App!

Get 24/7 study help with the Numerade app for iOS and Android! Enter your email for an invite.

Get the answer to your homework problem.

Try Numerade free for 7 days

Like

Report

$\bullet$ A steel wire has the following properties:$$\begin{array}{l}{\text { Length }=5.00 \mathrm{m}} \\ {\text { Cross-sectional area }=0.040 \mathrm{cm}^{2}} \\ {\text { Young's modulus = } 2.0 \times 10^{11} \mathrm{Pa}} \\ {\text { Shear modulus = } 0.84 \times 10^{11} \mathrm{Pa}} \\ {\text { Proportional limit }=3.60 \times 10^{8} \mathrm{Pa}} \\ {\text { Breaking stress }=11.0 \times 10^{8} \mathrm{Pa}}\end{array}$$The wire is fastened at its upper end and hangs vertically.(a) How great a weight can be hung from the wire without exceeding the proportional limit? (b) How much does the wire stretch under this load? (c) What is the maximum weight that can be supported?

a) 147 $\mathrm{kg}$b) 0.9 $\mathrm{cm}$c) 449 $\mathrm{kg}$

Physics 101 Mechanics

Chapter 11

Elasticity and Periodic Motion

Equilibrium and Elasticity

Periodic Motion

Simon Fraser University

Hope College

University of Sheffield

University of Winnipeg

Lectures

04:12

In physics, potential ener…

02:18

In physics, an oscillation…

03:00

A 4.0-m-long steel wire ha…

03:37

$\bullet$ A 5.0 kg mass is…

07:44

(a) Determine the maximum …

01:54

A steel cable 3.00 $\mathr…

04:44

A copper wire of length $3…

03:43

03:21

A $1.05-\mathrm{m}$ -long …

05:08

$\bullet$ In a museum exhi…

05:10

$\mathrm{A} 1.05-\mathrm{m…

02:26

In Fig. $12-45,$ suppose t…

04:54

A 1.05-m-long rod of negli…

08:00

A high-speed lifting mecha…

10:18

Determine the maximum weig…

02:37

$\bullet$ $\bullet \mathrm…

03:44

A wire of length $l_0$ and…

01:55

A 12.0 -kg mass, fastened …

02:52

Two ropes are connected to…

00:50

A 100-N weight is attached…

\bullet A uniform beam 4.0…

06:09

When a mass of 25 $\mathrm…

to do part a recall that the stress of an object is equal to the perpendicular force divided by the cross sectional area. So in this case, were given that we want the stress to be the proportional limit, which is 3.6 times 10 to the eighth. So we know F perp over a is equal to 3.6 times 10 to the eighth Pascal's, which is the proportional limit. In this case, the perpendicular forces just equal to the weight of the object. So wait, being W W over is now equal to 3.6 times 10 to the eighth best gals. And then we can solve this for W. Since we know the cross sectional area and so W is equal to 3.6 times 10 to the eighth. Pascal's Time's a cross sectional area, which is of being syrup 0.4 times 10 to the minus four, and this is a meter squared. So since everything is in S I u nits, whenever we plug this into the calculator, we're going to get an answer or Newton's. And that answer is one point for Times 10 cubed Nunes. And that's the maximum weight if you want to stay under the proportional limit here. And so the search party and Barbie, we want to figure out the change in length under this proportional limit. And so were called that young module asses Eagle to L. Not. Time's a perpendicular force over a telltale. So solving this for Delta L. We get Delta l is equal to the original length times the perpendicular force over Young's mom AngelesTimes cross sectional area And we know everything in the right hand side here. So he was plug in. Were you five for the originally time is one point for four times 10. Cute. This was what we found in party. We're going to divide by the Mongols. They give us 2.0 times 10 to the 11 and then the area which were used in part as 110.4 time stenting lives for and that's a meter square. When we do this out, I get nine times 10 to the minus three and this is in meters since everything used tears in this eye. And so that's the answer to part me. So for Parsi, we want to do that using the exact same setup as part, eh? Except in this case, F per over eh is equal to 11 times 10 to the eighth Pascal's. So this number here is different because this is now the breaking stress, but the exact process will be the same. And so we solve this out. We get that the wait. Is he going to four point for times 10? Cute. And so this is a little higher because we're allowing it to stress a little more. And so this is the final answer.

View More Answers From This Book

Find Another Textbook

In physics, potential energy is the energy possessed by a body by virtue of …

In physics, an oscillation is the repetitive variation, typically in time, o…

03:12

A barrel contains a 0.120 $\mathrm{m}$ layer of oil of density 600 $\mathrm{…

04:47

$\bullet$ $\bullet$ A mass $m$ is attached to a spring of force constant 75 …

02:33

The wax wears off so that the coefficient of kinetic friction is now $\mu_{k…

01:52

$\bullet$ In a series $R-L-C$ circuit, $R=300 \Omega, X_{C}=300 \Omega,$ and…

$\bullet($ a) Show that for an $R-L-C$ series circuit the power factor is eq…

09:37

The space shuttle. During the first stage of its launch, a space shuttle goe…

04:06

A parachutist relies on air resistance (mainly on her parachute) to decrease…

08:42

\bullet A cylinder contains oxygen gas $\left(\mathrm{O}_{2}\right)$ at a pr…

10:45

In Figure $18.44, \quad C_{1}=$ $6.00 \mu \mathrm{F}, \quad C_{2}=3.00 \mu \…

A chair of mass 12.0 $\mathrm{kg}$ is sitting on the horizontal floor; the f…