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$\bullet$ Between the poles of a powerful magnet is a cylindrical uniform magnetic field with a diameter of 3.50 $\mathrm{cm}$ and a strength of 1.40 $\mathrm{T}$ . A wire carries a current through the center of the field at an angle of $65.0^{\circ}$ to the magnetic field lines. If the wire experiences a magnetic force of $0.0514 \mathrm{N},$ what is the current flowing in it?

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Physics 101 Mechanics

Physics 102 Electricity and Magnetism

Chapter 20

Magnetic Field and Magnetic Force

Motion Along a Straight Line

Motion in 2d or 3d

Electric Charge and Electric Field

Gauss's Law

Current, Resistance, and Electromotive Force

Direct-Current Circuits

Magnetic Field and Magnetic Forces

Sources of Magnetic field

Electromagnetic Induction

Inductance

Rutgers, The State University of New Jersey

University of Michigan - Ann Arbor

University of Washington

McMaster University

Lectures

18:38

In physics, electric flux is a measure of the quantity of electric charge passing through a surface. It is used in the study of electromagnetic radiation. The SI unit of electric flux is the weber (symbol: Wb). The electric flux through a surface is calculated by dividing the electric charge passing through the surface by the area of the surface, and multiplying by the permittivity of free space (the permittivity of vacuum is used in the case of a vacuum). The electric flux through a closed surface is zero, by Gauss's law.

04:28

A magnetic field is a mathematical description of the magnetic influence of electric currents and magnetic materials. The magnetic field at any given point is specified by both a direction and a magnitude (or strength); as such it is a vector field. The term is used for two distinct but closely related fields denoted by the symbols B and H. The term "magnetic field" is often used to refer to the B field. In a vacuum, B and H are the same, whereas in a material medium, B is a component of H. In the latter case, H is the "magnetic field strength", and B is the "magnetic flux".

02:32

An electromagnet produces …

02:08

01:43

00:57

A wire that is $75 \mathrm…

00:49

A wire that is 1.50 m long…

03:53

A wire $2.30 \mathrm{~m}$…

01:07

A long wire carrying a 6.0…

01:48

A wire 1.80 $\mathrm{m}$ l…

A straight segment of wire…

01:52

02:43

A wire carries a 10.0 A cu…

So here the magnitude of the force is going to be equal to the magnitude of the magnetic field times, the current times, the length sign of fi. Here Fei is going to be equal to 65 degrees. And so we're trying to whether we know that the distances equaling 3.50 centimeters and based on the diagram, we can say that the length is going to be equal to the D, divided by sign of 65 degrees. So if we were Teo, think about this. If l equals sign of 65 degrees or D divided by sign of 65 degrees, we can simply solve for the current and say that here the current is going to be equal to F divided by B l sign of five. We know that fires also equal to 65 degrees. Therefore, this is simply equaling the force times the magnitude of the magnetic field times the distance D. So we can say that the current is going to be equal to 0.514 Newtons and then divided by it would be 1.40 Tesla's and then times here it would be a just d. So Dee is three points, five centimetres. So point 035 meters and this is giving us 1.5 amperes. So this should be our final answer. That is the end of the solution. Thank you for watching.

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