00:01
So for part a, the direction of the curvature, rather, we can look at the path of a particle and see the charge.
00:13
And the question, rather part a of the question is asking us how we do that.
00:19
So the direction of the curvature of the path tells us the direction of the force on the charge.
00:43
Now, if this is the same as the right -hand direction, if this is the same as the right -hand rule direction, the particle is positive.
01:05
Q is greater than zero kulums.
01:08
Again, this would be the right -hand direction for velocity and magnitude vectors.
01:14
So again, for we can say velocity and magnitude.
01:19
However, if it's opposite, we of course know that the charge is negative.
01:28
So the charge would be less than zero korems.
01:33
For part b, it's asking us, well, what would, like, what could, rather, what would we be able to find the velocity from a photograph? so we can say that mv equals the absolute value of the charge times r times b.
01:53
Now here r would be the radius of the curvature and b would be the again the magnitude of the magnetic field.
02:01
However from the photograph, so from photograph r can be measured.
02:09
The radius of the curvature of the path can be measured.
02:16
And from the photograph, if we have this and we have the charge and the magnetic field, we can find the momentum...