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$\bullet$ $\bullet$ The electric field due to a c…

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Problem 46 Hard Difficulty

$\bullet$ $\bullet$ (a) An electron is moving east in a uniform electric field of
1.50 $\mathrm{N} / \mathrm{C}$ directed to the west. At point $A$ , the velocity of the
electron is $4.50 \times 10^{5} \mathrm{m} / \mathrm{s}$ toward the east. What is the speed
of the electron when it reaches point $B, 0.375 \mathrm{m}$ east of point $A$ ?
(b) A proton is moving in the uniform electric field of part (a).
At point $A$ , the velocity of the proton is $1.90 \times 10^{4} \mathrm{m} / \mathrm{s},$ east.
What is the speed of the proton at point $B$ ?

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Physics 102 Electricity and Magnetism

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Chapter 17

Electric Charge and Electric Field

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Video Transcript

The first step to doing this problem is to figure out what the forces due to the electric field. And so we're going to use the equation. F is equal to absolute value of the charge times the electric field. In the case of an electron, the force will be opposite to the electric field, since the charge will be negative. And so it will actually speed up the electrons along this path here that we're focused on Blake and Q is 1.602 times 10 to the minus sign team grooms and then multiply by the electric field they give us, which is 1.5 and even super cool. Thanks. I get a force of two point for 03 times 10 2,000,000 19 noons. And again, this is positive because if the positive extraction is this way, this force will speed up the electron. After we find the force, we can calculate the acceleration by taking the force and divided by the mass. In this case, we're divided by the mass of the electron And so playing this and this in gives us exhilaration of positive. 2.638 times 10 to the 11 meters per second squared. So an extremely fast acceleration. Now that we know the exploration, we can do some cinematic equation to figure out what the final velocity is. So if the initial velocity is positive for 0.5 times 10 to the fifth, I'm just gonna avoid using units because they're all in sa units Already. The celebration is here. We know the distance. Travel explain. Sex not is equal to 0.375 and we want to figure out what the final velocity is to do this we're going to use the cannon back equation. He squared is equal to be not square plus two a x Mind sex. Not solving this for me. Give 6.33 times 10 to the fifth, and I'll add us here. This is a means for second. And so that completes a and we move on to party in part B. We're going to pretty much do the same thing, except the force is now going to be negative, says the charges. Now positive. So the charge would be The force will be along the electric field line, which is pointing opposite to the initial motion so we have a negative asset value of Q times. He and I just added in this negative because of what I just said regarding the Proton. And then now I'm just going to play in the charge of the proton and the electric field. I get negative 2.4 03 times 10 to the negative 19 years. This lets us calculate the acceleration as the force over the mass of a proton. And so this gives negative one point for 36 times, 10 to the eight meters per second squared. And then now I could do the same thing. Vienna is 1.9 times 10 to the fourth. The acceleration is here. Then this is travel exploits. Sex not is equal to 0.375 and we won't figure out what the final velocity is. So we're going to use the same chemical equation that were used in party. This guy right here, we're going to solve for the final velocity. And when we do that, we get 1.59 times 10 to the fourth. And so you see that it's slowed down in this case because the forces opposing the original velocity this is a minister second by life and that completes the answer

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Problem

$\bullet$ $\bullet$ The electric field due to a c…

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Watch More Solved Questions in Chapter 17

Video Transcript

Hugh D. Young

College Physics

Elyse Gonzalez

Zachary Mitchell

Aspen Fenzl

Jared Enns

This textbook answer is only visible when subscribed! Please subscribe to view the answer

College Physics

Elyse Gonzalez

Zachary Mitchell

Aspen Fenzl

Jared Enns

Hugh D. YoungCollege Physics

Elyse Gonzalez

Zachary Mitchell

Aspen Fenzl

Jared Enns

Hugh D. Young

College Physics