00:01
Alright, so the question was asking us, what is the period of the pendulum on the surface of the mars? okay, so we know the period on the surface of mars tm is equal to 2 pi times square root l over gm.
00:17
L is the length of pendulum.
00:20
Gm is the gravitational constant on mars.
00:24
Well, we know the gravitational constant on mars, which is 3 .71 meter per second square.
00:36
We also know the time period on earth is 1 .60 seconds.
00:44
So it seems like if we need to determine the period on mars, we need to determine the length of pendulum.
00:53
And we can determine the length of pendulum from the time period equation on earth, which is t .e equals 2 pi times square root log.
01:02
And g here is the gravitational constant on earth.
01:04
Okay, so if we do some arrangement, we get at l is just simply equal to g times t e square over 4 pi square, okay? and this will give us g, remember, it was 9 .8 meter per second square, times the time period on earth, which is 1 .60 second square...