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$\bullet$ Calculate the torque (magnitude and direction) about point $O$ due to the force $\vec{\boldsymbol{F}}$ in each of the situations sketched in Figure $10.41 .$ In each case, the force $\vec{\boldsymbol{F}}$ and the rod both lie in the plane of the page, the rod has length $4.00 \mathrm{m},$ and the force has magnitude 10.0 $\mathrm{N} .$

a) 40 $\mathrm{N} . \mathrm{m}$ counterclockwiseb) 34.6 $\mathrm{N.m}$ counterclockwisec) $=20 \mathrm{N} . \mathrm{m}$ counterclockwised) 17.32 $\mathrm{N.m}$ clockwisee) 0 $\mathrm{N} \cdot \mathrm{m}$f) $0 N_{ .} \mathrm{m}$

Physics 101 Mechanics

Chapter 10

Dynamics of Rotational Motion

Newton's Laws of Motion

Rotation of Rigid Bodies

Equilibrium and Elasticity

Rutgers, The State University of New Jersey

University of Michigan - Ann Arbor

University of Washington

Lectures

02:34

In physics, a rigid body is an object that is not deformed by the stress of external forces. The term "rigid body" is used in the context of classical mechanics, where it refers to a body that has no degrees of freedom and is completely described by its position and the forces applied to it. A rigid body is a special case of a solid body, and is one type of spatial body. The term "rigid body" is also used in the context of continuum mechanics, where it refers to a solid body that is deformed by external forces, but does not change in volume. In continuum mechanics, a rigid body is a continuous body that has no internal degrees of freedom. The term "rigid body" is also used in the context of quantum mechanics, where it refers to a body that cannot be squeezed into a smaller volume without changing its shape.

02:21

In physics, rotational dynamics is the study of the kinematics and kinetics of rotational motion, the motion of rigid bodies, and the about axes of the body. It can be divided into the study of torque and the study of angular velocity.

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Calculate the torque (magn…

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10.1 Calculate the torque …

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10_1

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10.1 Torque1_ Calculat…

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$\cdot$ Calculate the net …

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Calculate the net torque a…

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Calculate the torque of th…

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The object shown in Fig. 9…

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A force $\vec{F}=(6.00 \h…

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What are the magnitude and…

Hello. We're going to calculate on problem number one the torque of magnitude and direction. Um, about this point. O thes point owes six different scenarios here. All three of them are going to be using the same rod of length four meters. So in all cases, here are this our length here is four meters. You know when we're done rotating here and then all of them are forced. That's being applied. Is 10 millions difference years that the force is applied a little differently, depending on the situation. So let's go to our definition of what torque is. Work is force times, lever, arm and by lever arm. I mean, it's the perpendicular distance from the force to the pivot point and a. It's pretty simple because this is the perpendicular distance. So our torque here would be four times 10 and that's 14 8 meters now for direction. Okay, counter clockwise torque is considered positive and clockwise. Twerk. He's considered negative. This is a positive counterclockwise to work good. Our next Hunde we actually want need to extend out our lever arm kind of set up a little bit, but putting it a little too high here But the perpendicular distance would go to this point here. And since this is 1 20 be 60 so are perpendicular distance. Here, calculate artwork is four sign of 60 times that 10 that, if you calculate that out, is there before 0.6 meters again. This produces a counterclockwise Twerk, right? See now the same way looking for lever arm the force here or would be this perpendicular distance? The torque here would be four sign 30 times the 10 that calculates too. 20 meters again. This is also producing a counterclockwise tour. Hey, Difference Years or LeBron gives a tad shorter because our forces being applied at the midpoint instead of four here we're going to use to Torque is to interview. Lived here of the perfect distance again would be the sign of 60 times that force of 10 calculates, too. 17.3 ends. Yeah, you know, it's just time still. Well, now this somewhere, actually producing that clockwise tour Hey e and F for a little unique trying to find a perpendicular distance from the force to this pivot point. Well, you actually can't because it's lever arm here is zero. So it's torque is actually zero times that, Tim, Which gives us his zero torque. Actually, same thing's gonna happen here. Finding a perpendicular distance to the pivot point isn't gonna happen. So again, artwork is that zero times 10 cheese. Zero Newton meters. Thank you for learning with me today.

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