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$\bullet$ Figure 24.45 shows an object and its image formed by athin lens. (a) What is the focal length of the lens and what typeof lens (converging or diverging) is it? (b) What is the heightof the image? Is it real or virtual?

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a) 8.57 cmb) 1.875 mm

Physics 102 Electricity and Magnetism

Physics 103

Chapter 24

Geometric Optics

Electromagnetic Waves

Reflection and Refraction of Light

Cornell University

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Lectures

02:30

In optics, ray optics is a geometric optics method that uses ray tracing to model the propagation of light through an optical system. As in all geometric optics methods, the ray optics model assumes that light travels in straight lines and that the index of refraction of the optical material remains constant throughout the system.

10:00

In optics, reflection is the change in direction of a wavefront at an interface between two different media so that the wavefront returns into the medium from which it originated. Common examples include the reflection of light, sound and water waves. The law of reflection says that for specular reflection the angle at which the wave is incident on the surface equals the angle at which it is reflected. Reflection may also be referred to as "mirror image" or "specular reflection". Refraction is the change in direction of a wave due to a change in its speed. The refractive index of a material is a measure of its ability to change the direction of a wave. A material with a higher refractive index will change the direction of a wave to a greater degree than a material with a lower refractive index. When a wave crosses the boundary between two materials with different refractive indices, part of the wave is refracted; that is, it changes direction. The ratio of the speeds of propagation of the two waves determines the angle of refraction, which is the angle between the direction of the incident and the refractive rays.

03:55

$\bullet$ Figure 24.46 sho…

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.. Figure 24.47 shows an o…

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Figure 24.44 shows an obje…

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Figure 34.58 shows an obje…

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$\textbf{Figure P34.80}$ s…

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Figure 34.57 shows an obje…

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$\textbf{Figure P34.81}$ s…

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The figure below Shows an …

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Figure $\mathrm{P} 34.84$ …

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Figure $\mathrm{P} 34.85$ …

(I) A certain lens focuses…

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A converging lens with a f…

Okay, so for port Aye, we used the Thin Ones Equation. One of her image distance plus one over s over. One of our object distance puts one over image distance. It's equal to one over food collect. We're given in this problem that image distance are sorry. Object distance is 20 centimeters and image distance is 15 centimeters, both positive on that's equal to one over F. And so you work out the algebra are we work out the wrath Minnick and get that F focal length is plus 8.57 centimeters. And so this is positive creative zero, meaning that this land's is conversion. Lance, who's negatively would be diverting in part be used a magnification formula that is, he called too negative image distance over object distance. And so that's negative. 15 over 25. And so that's negative. 0.75 is the magnification. So So this object has ah, so the image will be shrunk relative to the object height. We also know that magnification is equal to image height over object height, so this is equal to tide over object height. That means that image height is negative. 0.75 times object height, which is 2.5 millimetres, has given the problem. So why Prime image height is negative. 1.8 millimetres and so negative. Why? Prime means that this is an inverted image. Furthermore, No, that s prime his positive. So this means that this is a really image, So it's a really inverted image that isthe de magnified.

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