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$\bullet$ Heart repair. A surgeon is using material from a donatedheart to repair a patient's damaged aorta and needs to know theelastic characteristics of this aortal material. Tests performedon a 16.0 $\mathrm{cm}$ strip of the donated aorta reveal that it stretches3.75 $\mathrm{cm}$ when a 1.50 $\mathrm{N}$ pull is exerted on it. (a) What is theforce constant of this strip of aortal material? (b) If the maxi-mum distance it will be able to stretch when it replaces theaorta in the damaged heart is $1.14 \mathrm{cm},$ what is the greatestforce it will be able to exert there?

40 $\mathrm{N} / \mathrm{m}$0.456 $\mathrm{N}$

Physics 101 Mechanics

Chapter 5

Applications of Newton's Law

Motion Along a Straight Line

Motion in 2d or 3d

Newton's Laws of Motion

Applying Newton's Laws

Cornell University

University of Washington

Simon Fraser University

University of Winnipeg

Lectures

04:16

In mathematics, a proof is…

04:48

In mathematics, algebra is…

01:49

A surgeon is using materia…

02:48

B10 Heart Repair. A surgeo…

00:57

Calculate the maximum forc…

01:06

BIO Force exerted by heart…

04:06

Artery blockage. A medical…

07:46

A medical technician is tr…

00:59

The left side of the heart…

03:45

The power output of the he…

05:31

Tendons are strong elastic…

$\bullet$ Tendons. Tendons…

01:56

During normal beating, the…

00:56

BIO Human Heart Force The …

02:14

A heart defibrillator pass…

03:18

Left ventricle pumping The…

00:45

Calculate the Hall voltage…

02:07

BIO Power of the Human Hea…

01:29

Calculate the average pres…

04:37

$\bullet$ $\bullet$ The po…

01:10

The pressure drop along a …

06:13

In an aortic aneurysm, a b…

so hooks. Law states that f equals K X. Here we have x a cz as 6.75 6.75 centimeters, so that's divided by 100. That's 1000.675 meters because we want things in terms of meters or not centimetres but Esso in part a. We have a force given. So the constant the spring constant chaos just ever Rex and forces 1.5 neatness access point 0675 meters and so spring constant is 40 newtons per meters. In probie, we want the maximum force max. That will be K X. And so we found care to be 40 per meters times x, which in this case is 1.4 centimeters, huh? 1.1 foreign groups, 1.14 centimetres. So that's 1.1 for over 100 meters and this gives us 0.456 New says the maximum force

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