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$\bullet$ Human entropy. A person having skin of surface area1.85 $\mathrm{m}^{2}$ and temperature $30.0^{\circ} \mathrm{C}$ is resting in an insulated roomwhere the ambient air temperature is $20.0^{\circ} \mathrm{C} .$ In this state, a person gets rid of excess heat by radiation. By how much doesthe person change the entropy of the air in this room each second? (Recall that the room radiates back into the person and that the emissivity of the skin is 1.00.)

The entropy of the air in the room changed by $\Delta S_{n c t}=0.38 \mathrm{J} / \mathrm{K}$ per second.

Physics 101 Mechanics

Chapter 16

The Second Law of Thermodynamics

Temperature and Heat

Thermal Properties of Matter

The First Law of Thermodynamics

Rutgers, The State University of New Jersey

Simon Fraser University

University of Winnipeg

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given surface area off the skin that it is represented by A which is equal to 1.85 meet at its worst Cambridge it is given 3 30 degrees centigrade. Now we will convert into Kelvin So 30 plus 2 73 Now it is converted into Kelvin, which is equal to 303 killed it ambient air temperature. Let it is represented by TS, which is 20 degrees Integrate Now we will convert into a Taliban 20 plus 2 73 This converted into elven which is equal to 293. Kelvin, we have to find that changing and profit here M s activities given is equal to one. So we have to find that changing and property. You know that Delta X is equal to e sigma in two times into temperature. So he's about four minus ps to depart for upon Yes. Now we will substitute the value in this. So changing and drop with Delta s is equal to 1.85 in 212 five point 67 and took 10 to the four minus eight into one and 30 due to the poor four minus to 93 for the gold four upon 293 Calvin. So after solving this, we will get changing and proper. Delta s is equal to 0.379 Elven funny 379 zu kelvin. So we can say that room so biggest their room against the and property, so this order will increase.

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