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A particle with a charge of $-2.50 \times 10^{-8}…

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Problem 7 Medium Difficulty

$\bullet \mathrm{A}^{9}$ Be nucleus containing four protons and five neutrons has a mass of $1.50 \times 10^{-26} \mathrm{kg}$ and is traveling vertically upward at 1.35 $\mathrm{km} / \mathrm{s} .$ If this particle suddenly enters a horizontal magnetic field of 1.12 T pointing from west to east, find the
magnitude and direction of its acceleration vector the instant after it enters the field.

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Physics 102 Electricity and Magnetism

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Chapter 20

Magnetic Field and Magnetic Force

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Video Transcript

for the given problem. We have a following situation. A brilliant item that contains ah four brought on and ah, five new drawn is ah, traveling upward and said I lied Enters romantic feel that points from west to east. So let's say this is the rest Here. This is the east. Brilliant, mate. Um, he's going upward, and we level this north and this is the South. We also level um J Kim Small Jake kept for the unit director in upward direction. And I kid ah, in the direction off the man take field will be here then. No, we can write the force by writing a force. We can find X elation. Ah, from Newton's second law, that is f is equal to m A. So we'll first find the force and substitute the mass, um, for the given problem and then find the acceleration. So, in order to find the force foreskin, dirty knees, um, que we cross b sign better your scientists because they r b and we are perpendicular to each other. Therefore, sign that there will be 90. Then we can find the force by substituting the charges. Um, so four times the charge on each brought on witches, 1.602 times 10 to the power, um, tend to the bar were minus 19 minus 19 times. Um, Speed, which is 1.35 times 10 to the power of three meter per second time's. The Mayfield, which is 1.1 to Tesla, were signed nineties one here. So this will give us a force. So for mine 0.68 times 10 to the power minus 16 Newton Oh, then we confined. Ah, the direction off the force will be by taking the cross product off the unit vectors for B and B, which is Jay Cross. I will give us a minus k. So this will be in the direction off the north, so the force will be in the north direction. From there, we can also find a direction off the exploration because the direction of force and exploration of the Chandler um So the direction off the explosion will be also towards the ah more tthe we can find them a chewed off acceleration that is force divided by mass. So substituting the value for a mass given in the problem which is 1.5 for the instant, about minus 26 kg for four part owner and five neutron. Um, we get the exploration to be 6.458 times 10 to the power 10 meter per second square in the direction will be in north.

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Problem

A particle with a charge of $-2.50 \times 10^{-8}…

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College Physics

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Top Physics 102 Electricity and Magnetism Educators

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Watch More Solved Questions in Chapter 20

Video Transcript

Hugh D. Young

College Physics

Andy Chen

Marshall Styczinski

Jared Enns

Meghan Miholics

This textbook answer is only visible when subscribed! Please subscribe to view the answer

College Physics

Andy Chen

Marshall Styczinski

Jared Enns

Meghan Miholics

Hugh D. YoungCollege Physics

Andy Chen

Marshall Styczinski

Jared Enns

Meghan Miholics

Hugh D. Young

College Physics