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$\bullet \mathrm{A}^{9}$ Be nucleus containing four protons and five neutrons has a mass of $1.50 \times 10^{-26} \mathrm{kg}$ and is traveling vertically upward at 1.35 $\mathrm{km} / \mathrm{s} .$ If this particle suddenly enters a horizontal magnetic field of 1.12 T pointing from west to east, find themagnitude and direction of its acceleration vector the instant after it enters the field.

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Physics 101 Mechanics

Physics 102 Electricity and Magnetism

Chapter 20

Magnetic Field and Magnetic Force

Motion Along a Straight Line

Motion in 2d or 3d

Electric Charge and Electric Field

Gauss's Law

Current, Resistance, and Electromotive Force

Direct-Current Circuits

Magnetic Field and Magnetic Forces

Sources of Magnetic field

Electromagnetic Induction

Inductance

University of Michigan - Ann Arbor

University of Washington

University of Winnipeg

McMaster University

Lectures

18:38

In physics, electric flux is a measure of the quantity of electric charge passing through a surface. It is used in the study of electromagnetic radiation. The SI unit of electric flux is the weber (symbol: Wb). The electric flux through a surface is calculated by dividing the electric charge passing through the surface by the area of the surface, and multiplying by the permittivity of free space (the permittivity of vacuum is used in the case of a vacuum). The electric flux through a closed surface is zero, by Gauss's law.

04:28

A magnetic field is a mathematical description of the magnetic influence of electric currents and magnetic materials. The magnetic field at any given point is specified by both a direction and a magnitude (or strength); as such it is a vector field. The term is used for two distinct but closely related fields denoted by the symbols B and H. The term "magnetic field" is often used to refer to the B field. In a vacuum, B and H are the same, whereas in a material medium, B is a component of H. In the latter case, H is the "magnetic field strength", and B is the "magnetic flux".

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An alpha particle (a He nu…

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A particle with mass $1.81…

02:39

\bullet A particle with ma…

04:20

A lithium- 5 nucleus $\lef…

05:30

04:47

05:58

02:54

04:02

A particle with mass 1.81 …

03:20

01:05

Assume that all charged pa…

for the given problem. We have a following situation. A brilliant item that contains ah four brought on and ah, five new drawn is ah, traveling upward and said I lied Enters romantic feel that points from west to east. So let's say this is the rest Here. This is the east. Brilliant, mate. Um, he's going upward, and we level this north and this is the South. We also level um J Kim Small Jake kept for the unit director in upward direction. And I kid ah, in the direction off the man take field will be here then. No, we can write the force by writing a force. We can find X elation. Ah, from Newton's second law, that is f is equal to m A. So we'll first find the force and substitute the mass, um, for the given problem and then find the acceleration. So, in order to find the force foreskin, dirty knees, um, que we cross b sign better your scientists because they r b and we are perpendicular to each other. Therefore, sign that there will be 90. Then we can find the force by substituting the charges. Um, so four times the charge on each brought on witches, 1.602 times 10 to the power, um, tend to the bar were minus 19 minus 19 times. Um, Speed, which is 1.35 times 10 to the power of three meter per second time's. The Mayfield, which is 1.1 to Tesla, were signed nineties one here. So this will give us a force. So for mine 0.68 times 10 to the power minus 16 Newton Oh, then we confined. Ah, the direction off the force will be by taking the cross product off the unit vectors for B and B, which is Jay Cross. I will give us a minus k. So this will be in the direction off the north, so the force will be in the north direction. From there, we can also find a direction off the exploration because the direction of force and exploration of the Chandler um So the direction off the explosion will be also towards the ah more tthe we can find them a chewed off acceleration that is force divided by mass. So substituting the value for a mass given in the problem which is 1.5 for the instant, about minus 26 kg for four part owner and five neutron. Um, we get the exploration to be 6.458 times 10 to the power 10 meter per second square in the direction will be in north.

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