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$\bullet$ Monochromatic light from a distant source is incident on aslit 0.750 mm wide. On a screen 2.00 m away, the distancefrom the central maximum of the diffraction pattern to the firstminimum is measured to be 1.35 $\mathrm{mm} .$ Calculate the wave-length of the light.

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506 nm

Physics 102 Electricity and Magnetism

Physics 103

Chapter 26

Interference and Diffraction

Electromagnetic Waves

Reflection and Refraction of Light

Cornell University

Hope College

University of Sheffield

University of Winnipeg

Lectures

02:30

In optics, ray optics is a geometric optics method that uses ray tracing to model the propagation of light through an optical system. As in all geometric optics methods, the ray optics model assumes that light travels in straight lines and that the index of refraction of the optical material remains constant throughout the system.

10:00

In optics, reflection is the change in direction of a wavefront at an interface between two different media so that the wavefront returns into the medium from which it originated. Common examples include the reflection of light, sound and water waves. The law of reflection says that for specular reflection the angle at which the wave is incident on the surface equals the angle at which it is reflected. Reflection may also be referred to as "mirror image" or "specular reflection". Refraction is the change in direction of a wave due to a change in its speed. The refractive index of a material is a measure of its ability to change the direction of a wave. A material with a higher refractive index will change the direction of a wave to a greater degree than a material with a lower refractive index. When a wave crosses the boundary between two materials with different refractive indices, part of the wave is refracted; that is, it changes direction. The ratio of the speeds of propagation of the two waves determines the angle of refraction, which is the angle between the direction of the incident and the refractive rays.

01:24

Monochromatic light from a…

01:21

02:15

02:35

A beam of monochromatic li…

00:55

The first thing to realize in this problem is that the small angle approximation is valid because the distance to the slit is so much larger than the distance between the maximum that we're concerned with. So this ratio is really small and so we can imply this formula which takes advantage of the small angle approximation. Now we're told that why one this is just giving it. The problem is equal to 1.35 millimetres, and ultimately we want to sell for this wavelength. And so solving for this way of life I get Lambda is equal to why one time's a where are you? Because he already plugged in that time was one here. So really, I need Teo to turn this up until one. We want the first constructive interference. And so it was going to be one just to clean this up, I'm going to rewrite it. So this is why I'm one times ever are is the width of the slip that we're going through. Why one is the distance on the screen between zero point and the first maximum and ours the distance to the screen. We know all these values. Why want its 1.35 times 10 to the minus third is 0.75 times 10 to the minus turd. Those are both in meters, by the way, and ours two meters. And so this is our being 560 centimetres. You'll get a really small value out here, but that'll be in meters. So if you wantto converted into Nana meters, this is what you'll get here. And so this is the wavelength of light that you want to use to get the conditions of the problem and that completes this.

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