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$\bullet$ On a very muddy football field, a $110-$ kg linebacker tack-les an 85 -kg halfback. Immediately before the collision, thelinebacker is slipping with a velocity of 8.8 $\mathrm{m} / \mathrm{s}$ north and the halfback is sliding with a velocity of 7.2 $\mathrm{m} / \mathrm{s}$ east. What isthe velocity (magnitude and direction) at which the two players move together immediately after the collision?

$v_{2}=5.87 \mathrm{m} / \mathrm{s}, 57.7^{\circ}$ north of east

Physics 101 Mechanics

Chapter 8

Momentum

Physics Basics

Kinetic Energy

Potential Energy

Energy Conservation

Moment, Impulse, and Collisions

University of Sheffield

University of Winnipeg

McMaster University

Lectures

04:16

In mathematics, a proof is…

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In mathematics, algebra is…

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On a very muddy football f…

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(II) A $95 .$ kg halfback …

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A football player with a m…

08:22

An 88 kg fullback moving e…

04:27

(I) A 110-kg tackler movin…

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Two football players colli…

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A 92 -kg fullback, running…

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So in this case we have to footballers a linebacker with weight, 110 kilograms on velocity, 8.8 meters per second and 1/2 back going with the velocity 7.2 meters per second and max 85 kilograms. They both collide at a certain point on DH, then start moving together in some direction. Let's say this direction makes an angle ofthe theatre with the horizontal and the velocity would be something we obviously the mass would be the sums off the two masses one ten 10 plus 1 85 and that would be 195 kilograms. Now, as usual, will choose exactly horizontally and y axis vertically. We want to find out the magnitude of the velocity and the direction, which means this angle. So now let's say this velocity has to conference. I mean, obviously it has to confidence re X and B. Bye, Right? We y on the X now release conservation of energy in two directions X and Y delusions to find out the X and y now initially going for X direction. The initial what went on in X direction before the collision would be simply they went off the halfback because the line doc's going down linebackers mourned him would be completely in the vertical direction. And they have that morning movie mask 85 kilograms times the last e 7.2 meters per second. Now the final momentum in the X axis in the extraction would be masked off the off. Put the players times the ex con print off the velocity on mass off what the players would be. 1 95 kilograms and the velocity would be pX. And because there are no other external forces and friction is negligible, we can say moment of his guns out and hands if the initial and finally moment does Melinda in the X axis the extraction all the same. Which gives us the X Times 1 95 is equal to 7.2 times 85 calling this equation forget we accept equal to 3.14 meters per second. Now for similarly for why access? The initial moment of in my direction is simply the momentum off the heavier player. That would be masked Time's philosophy 8.8 meters per second. Now the final momentum invite direction would be the mass ofthe other players multiplied by the white component of Velocity v i. Viv I. That would be 195 times. We buy again using conservation of momentum we see 1 95 is equal to 110 multiplied by sorry, 110 multiplied by 8.8 This cues Levi is equal to 4.96 major over Sigan Now that we have got to leave what on the ex? We can see that the magnitude of the velocity V is simply wrote off. The X squared plus y squared is in the fight about in the room and this turns out to be 5.64 meter per second. Now, as far as the angle ghost we know the Tita you stand in worse off B y by the X, the white continent of velocity divided by the ex confident of velocity. It's turns out to be 57.7 degrees, just 58 degrees. Use only two significant digits because our velocities I have only to say David indigents. So this combined the two players together, who at the velocity off 5.64 meters per second at an angle of 58 degrees not off east

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