00:01
Alright guys, let's take a look at the question.
00:02
So the question was asking us to find out the heat that is required from temperature 20 degrees celsius to 210 degrees celsius.
00:11
Well, first we know the heat that required to raise from certain temperature to certain temperature for a single item.
00:19
It's q equal to mc times delta t.
00:22
Q is the required heat, m is the mass of that item, c is the specific heat for a single item, and the delta is the changing temperature.
00:30
So now, well, let's look at the required heat for aluminum.
00:37
Okay? so we know the mass of aluminum is 1 .6 kilogram and the specific heat for the aluminum is 0 .91 times 10 to power 3, jou per kilogram times kelvin.
00:50
And the mass for the iron is 0 .3 kilogram and a specific heat for the iron is 0 .47 times 10 to power 3 per kilogram 10 kelvin.
01:03
Okay, so let's figure out the heat required for aluminum first, which is q1 equal to m1 times c1, which will give us 1 .6 kilogram times .91 times .91 times 10 to power 3 jou over kilogram times kelvin, times 190 degrees celsius.
01:22
Because the changing temperature is from 20 degrees celsius to 210 degrees celsius...