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$\bullet$ Perfectly rigid containers each hold $n$ moles of ideal gas, one being hydrogen $\left(\mathrm{H}_{2}\right)$ and other being neon $(\mathrm{Ne}) .$ If it takes 100 $\mathrm{J}$ of heat to increase the temperature of the hydrogen by $2.50 \mathrm{C}^{\circ},$ by how many degrees will the same amount of heat raise the temperature of the neon?

$4.1666^{\circ} C$

Physics 101 Mechanics

Chapter 15

Thermal Properties of Matter

Temperature and Heat

The First Law of Thermodynamics

The Second Law of Thermodynamics

Cornell University

University of Michigan - Ann Arbor

McMaster University

Lectures

03:15

In physics, the second law…

03:25

The First Law of Thermodyn…

08:03

Perfectly rigid containers…

10:00

One mole of neon, a monato…

02:22

A monatomic ideal gas in a…

05:00

Three moles of neon expand…

09:30

Two ideal gases have the s…

03:05

A rigid container holds $0…

06:32

One mole of an ideal monat…

07:26

$\bullet$ (a) If you suppl…

00:51

At what temperature will 1…

04:27

Suppose two 200.0-L tanks …

02:04

What mass of neon gas is r…

02:15

01:05

A sample of hydrogen $\lef…

03:30

(I) A 1.00 -mol sample of …

02:44

A container holds $1.0 \ma…

01:22

A $2.50-$ L volume of hydr…

01:01

A rigid container bolds hy…

02:11

A mole of ideal monatomic …

Calculate the number of mo…

02:08

At what temperature does 4…

When 100 joes of heat is applied to n moles of hydrogen, then it changes its temperature by 2.50 degree celsius. So here heat supplied is equal to 100 joules delta t is equal to 2.50 degree celsius, so the relation for q q is equal to n times c v times delta t here, cum 100 joule is equal to number of moles that and the value of c V, that is smaller, specific heat at constant volume for hydrogen. Here we take. Hydrogen is a deal case, as hydrogen is diatomic gas, so molar specific heat for hydrogen is 5 upon 2 or and checking temperature for hydrogen is 2.50 degree celsius. Let be signame this equation. 1 again, 100 joule of heat is applied to an moles of neon gas and we want to calculate the change in temperature in neon. Yes, so here heat supplied is equal to 100 joules. We want to calculate the change in temperature. Here we take neon guess as our deal guess. Neon is a monatomic guess, so the molar specificate for noon is equal to 3 upon 2 r. So again, by taking the relation, q is equal to n c v delta t here. Cum is 100 joules, which is equal to n and c for s 3 upon 2 into r into delta t let his name this equation 2. Now by comparing equation 1 and 2, we have the left hand. Sides of both equations are equal, so the right hand side also be equal, so we get by comparing equation 1 and 2. We have n into 3 by 2 r into delta. T is equal to n into 5 by 2 r into 2.50 degree celsius. To and from here we will cancel an a then r and r 2 and 2, so we get delta t is equal to 5 upon 3 into 2.5 degrees celsius. So change in temperature is equal to 4.1666 degrees celsius. This is the change in temperature of neon gas, 100 joules of feupplied.

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