Download the App!

Get 24/7 study help with the Numerade app for iOS and Android! Enter your email for an invite.

Get the answer to your homework problem.

Try Numerade free for 7 days

Like

Report

$\bullet$ Sketch a graph of (a) the nonrelativistic Newtonian kineticenergy as a function of speed $v,$ (b) the relativistic kineticenergy as a function of speed $v$ . In both cases, start from $v=0$and include the region where $v \rightarrow c .$ Does either of thesegraphs extend beyond $v=c ?$

(b) For relativistic motion, kinetic energy $k=\frac{m c^{2}}{\sqrt{1-\frac{v^{2}}{c^{2}}}}-m c^{2},$ so the graph will be as shown in the

Physics 101 Mechanics

Chapter 27

Relativity

Gravitation

Rutgers, The State University of New Jersey

University of Michigan - Ann Arbor

University of Washington

Hope College

Lectures

03:55

In physics, orbital motion is the motion of an object around another object, which is often a star or planet. Orbital motion is affected by the gravity of the central object, as well as by the resistance of deep space (which is negligible at the distances of most orbits in the Solar System).

03:18

Sir Isaac Newton described the law of universal gravitation in his work "Philosophiæ Naturalis Principia Mathematica" (1687). The law states that every point mass attracts every single other point mass by a force pointing along the line intersecting both points. The force is proportional to the product of the two masses and inversely proportional to the square of the distance between them.

0:00

Make a graph of the relati…

01:45

(a) Even in the relativist…

03:17

08:45

$\bullet$ Using both the n…

02:13

This problem is intended t…

all right. In part A, we want a graph the kinetic energy of a new object as a function of its velocity. And because the kinetic energy in a non relativistic setting goes is V squared, this is going to look like a parabola. And when V is equal to C, the kinetic energy takes on a value of 1/2 emcee squared. Now, in part B, we want to use the relativistic um, kinetic energy, which is K e is equal to M C squared gamma minus one. And this, um, has a somewhat similar shape on lee a cz as V approaches si the kinetic energy grows without bound because you're basically since gamma is equal to one over the square of one minus v squared over C squared. Sorry over C squared. As V gets close to see, you're basically dividing by zero. And so this thing will blow up. You have been asked himto sea and technically, in this 1st 1 the graph shouldn't extend me up and see anyway, because that's not possible. But this equation basically breaks down. As you've lost, he gets closer to see you need to be using this formula to get on accurate value for the kinetic energy

View More Answers From This Book

Find Another Textbook

09:26

(a) Calculate the total binding energy (in MeV) of the nuclei of $^{56} \mat…

04:04

(III) Assume in Problem 44 that the speeder's speed is not known. If th…

03:25

(II) At $t=0,$ a particle starts from rest at $x=0, y=0$ , and moves in the …

03:51

$$\begin{array}{l}{\text { (II) Figure } 36 \text { shows two vectors, } \ve…

03:01

Suppose a car manufacturer tested its cars for front-endcollisions by ha…

00:53

For an ideal gas with 9 degrees of freedom, the molar heat capacity at const…

04:35

$\bullet$ $\bullet$ Three negative point charges liealong a line as show…

05:05

$\bullet$$\bullet$ Two point charges are separated by 25.0 $\mathrm{cm}$ (se…

03:24

A futuristic spaceship flies past Pluto with a speed of 0.964 $\mathrm{c}$

02:21

(II) A 75 -m-long train begins uniform acceleration from rest.The front …