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$\bullet$ Solar collectors. A well-insulated house of moderate size ina temperate climate requires an average heat input rate of20.0 $\mathrm{kW}$ . If this heat is to be supplied by a solar collector withan average (night and day) energy input of 300 $\mathrm{W} / \mathrm{m}^{2}$ and acollection efficiency of $60.0 \%,$ what area of solar collector isrequired?

111.1 $\mathrm{m}^{2}$

Physics 101 Mechanics

Chapter 16

The Second Law of Thermodynamics

Temperature and Heat

Thermal Properties of Matter

The First Law of Thermodynamics

Cornell University

Rutgers, The State University of New Jersey

University of Michigan - Ann Arbor

McMaster University

Lectures

03:15

In physics, the second law of thermodynamics states that the total entropy of an isolated system can only increase over time. The total entropy of a system can never decrease, and the entropy of a system approaches a constant value as the temperature approaches zero.

03:25

The First Law of Thermodynamics is an expression of the principle of conservation of energy. The law states that the change in the internal energy of a closed system is equal to the amount of heat energy added to the system, minus the work done by the system on its surroundings. The total energy of a system can be subdivided and classified in various ways.

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A well-insulated house of …

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an example of sizing solar energy array for collecting heat for a home. Um So these are not electrical panels. These are panels that hold some sort of working substance that heats up with energy from the sun and then that heat is transferred into the house. But what we know about this house is it needs heat absorption at a rate of 20 kW um for a typical energy consumption day, the panels are specified at 300 watts per meter squared. And being conservative, they have a 60 efficiency, which means that they can provide a queue dot of 180 watts per meter squared times the area of the panels put together. So equating the two energy need to the energy supply, we can determine that what the area is. Okay, So this is the need and this is the supply. And let's just equate those. And then we get um 180 watts per meter squared times the area equals 20 Times 10 to the 3rd watts. And that gives us an area of 111 m squared, which is substantial. That's 10 m, roughly by 10 m, maybe more like 10.5 m by 10.5 m, So that's a fairly large structure.

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