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$\bullet$ The sun produces energy by nuclear fusion reactions, inwhich matter is converted into energy. By measuring the amountof energy we receive from the sun, we know that is producingenergy at a rate of $3.8 \times 10^{26} \mathrm{W}$ . (a) How many kilograms ofmatter does the sun lose each second? Approximately how manytons of matter is this? ( b) At this rate, how long would it take thesun to use up all its mass? (See Appendix E.)

$=4.714 \times 10^{20} \mathrm{s}$

Physics 101 Mechanics

Chapter 27

Relativity

Gravitation

Cornell University

Rutgers, The State University of New Jersey

University of Winnipeg

Lectures

03:55

In physics, orbital motion is the motion of an object around another object, which is often a star or planet. Orbital motion is affected by the gravity of the central object, as well as by the resistance of deep space (which is negligible at the distances of most orbits in the Solar System).

03:18

Sir Isaac Newton described the law of universal gravitation in his work "Philosophiæ Naturalis Principia Mathematica" (1687). The law states that every point mass attracts every single other point mass by a force pointing along the line intersecting both points. The force is proportional to the product of the two masses and inversely proportional to the square of the distance between them.

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The sun produces energy by…

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The sun radiates energy at…

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The sun produces energy at…

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The Sun produces energy at…

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The Sun radiates energy in…

are in part A. We're told that the power output of the sun is 3.8 times 10 to the 26 watts, and we want to know what mass lost per second is associated with this power output. So we can set 3.8 times 10 to the 26 equal to M C squared. That's for energy contained in a mass and yes and so the mass consumed per second is going to be 3.8 times 10 to the 26 divided by three times 10 to the A squared and this comes out too. 4.2 times tend to the nine kilograms. If we want to express this in tons, we have to multiply by 2.2 pounds per kilogram and to bite out by 2,000 in this gives 4.6 times 10 to the six tons in part B. Ro asked how long it will take the sun to consume all of its mass if the mass is given by ah 1.99 times 10 to the 30. So this is just 1.99 times 10 to the 30 divided by 4.2 sorry. This should be kilograms per second back here on 4.2 times 10 to the nine kg per second equals 4.7 times 10 to the 20 seconds. And this is equal toe 1.5 times 10 to the 13 years.

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