00:03
Alrighty.
00:05
So in this problem, we have a soap bubble.
00:11
We're just going to zoom in on the soap bubble wall real nice and close.
00:19
So we're shining light into our soap bubble from air, which has an index of refraction of one.
00:28
There's air inside of it.
00:31
And then the wall of our soap bubble has an index of refraction of 1 .33.
00:39
Now, if you're thinking, out exactly what we're doing, we need to take a second to draw all of our beautiful light paths.
00:48
So when we have our light coming in, when it hits this surface, it's going to be partially reflected there, and then partially transmitted, and then get reflected here and come back out.
01:14
So there's two important parts in this process.
01:17
When we get a reflection here and when we get a reflection here.
01:23
So at this first junction, when we're bouncing here, we're going from an index of refraction 1 to an index of refraction 1 .33.
01:36
So when you go from a smaller index of refraction and reflect off of a higher index of refraction, that's going to give you a phase shift of half of a cycle.
01:53
And when down here we come from a higher index of a fraction and reflect off of a lower one, there's no phase shift.
02:07
So this throws our two beams that get reflected out of the soap bubble out of phase by 180.
02:15
So if we're going to view this reflection with our eyeballs, we're going to be viewing the constructive interference.
02:26
Because if it's destructive, we're not going to see it.
02:28
It's going to be a nice dark spot.
02:32
But remember from the section two sections ago, 26 .1, if the two beams are out of phase, your constructive interference occurs at half integer values.
02:50
So when we're talking about our thin films, the relationship here between m lambda and our thin films is m plus a half, because they're out of phase, lambda of the film, so i'm going to put a little f there, is equal to two times the thickness of our thin film.
03:17
So a thing to specify here is that this is the thickness of our thin film.
03:27
Cool.
03:28
So all of our phase shift business is happening in here, and we're getting the path length different.
03:36
Which allows for constructive and destructive interference from traveling twice this thickness.
03:44
So that's where the two t comes from because our path link is being thrown off by one t, 2t, and then it's going back out.
03:55
All right.
03:56
So now the other important thing to note that they don't really describe super clearly in the book is that this wavelength is the wavelength inside the film because this.
04:07
That's where this shifting is occurring.
04:11
So inside the film, i have an index of refraction that is not equal to one...