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$\bullet$ Three forces are applied to a wheel of radius $0.350 \mathrm{m},$ as shown in Fig. $10.43 .$ One force is perpendicular to the rim, one is tangent to it, and the other one makes a $40.0^{\circ}$ angle with the radius. What is the net torque on the wheel due to these three forces for an axis perpendicular to the wheel and passing through its center?
$0.31 \mathrm{N} \cdot \mathrm{m},$ Clockwise
Physics 101 Mechanics
Chapter 10
Dynamics of Rotational Motion
Newton's Laws of Motion
Rotation of Rigid Bodies
Equilibrium and Elasticity
Cornell University
University of Washington
University of Winnipeg
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loafer problem number three were asked to find the net torque on this wagon wheel of a radius of 0.3 five meters. Now there are three forces acting on this wagon wheel. We have a force here of 11.9 Newtons. We have one that's a a kn angle of 40 degrees, and that's is 14.6 news when we have one here, that 8.5 Knin's so, by definition, net torque is equal to the net. Force is some of the of the forces times there lever arms. We have three forces, so we're gonna be looking for how those three forces, whether or not they give us a torque. Now remember, level arm is defined as the particular distance from the pivot point or the center. This 11.9 it's the lever arm would be considered zero because it goes through the center. Um, also note that torques are considered positive if they provide a counterclockwise rotation. So this 8.5 torque would produce a counter clock or force would produce a counterclockwise rotation. Where is this? 14.6 force would actually produce a clockwise, so this would be considered a negative tour. So on our 14.6, it's a negative torque, and it's lever arm because it is at an angle. For particular distance would be the radius 0.35 times sign of 40 degrees and our final positive torque would be 8.5. It's lever arm is the radius of the wheel. 0.35 Coming those up. Get a negative. 0.31 new leader the negative. Here. Denounce that we have a clockwise torque. Thank you for learning with me.
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