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$\bullet$ To warm up for a match, a tennis player hits the 57.0 g ballvertically with her racket. If the ball is stationary just before itis hit and goes 5.50 $\mathrm{m}$ high, what impulse did she impart to it?

$J=0.59 \mathrm{kg} \cdot \mathrm{m} / \mathrm{s}$

Physics 101 Mechanics

Chapter 8

Momentum

Physics Basics

Kinetic Energy

Potential Energy

Energy Conservation

Moment, Impulse, and Collisions

University of Washington

Hope College

University of Sheffield

University of Winnipeg

Lectures

03:23

In physics, mechanical ene…

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In physics, a conservative…

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$\bullet$ Tennis, anyone? …

0:00

A tennis ball of mass 57.0…

09:10

03:00

A tennis player receives a…

01:53

When serving a tennis ball…

01:10

03:58

02:18

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A tennis player hits a 58.…

02:35

To make a bounce pass, a p…

04:09

At serve, a tennis player …

08:09

At scrve, a tennis player …

02:36

A 0.280-kg volleyball appr…

19:27

The mass of a regulation t…

01:48

A tennis ball of mass $0.0…

02:09

When a 58 -g tennis ball i…

04:35

Just before it is struck b…

01:07

SSM A volleyball is spiked…

01:41

A tennis ball is struck in…

02:12

A soft rubber ball $(m=0.5…

were given that the tennis ball was hit in the upward direction. So initially it was stationary on. Let's say the hitting with the tennis bag gave it a velocity off. I'm It went up to the height ofthe 5.5 meters. After the hitting. We want to find out the impulse that Wass imparted in on that tennis player off line on the body now. Initially, the Pollos stationery on DH, She applied the tennis player of light of force for some time, period and give it gave it an impulse that produces a change in momentum equal to the impulse. We know that initially the impulse for zero on hence, after the hit it gained some Wyndham. Let's say pee on this moment, I'm corresponds to a velocity V on this velocity. We took it to 5.5 meters against the gravitational force, so let's start reverse now because the object went the tennis ball went toe hide off 5.5 meters. We can find the initial velocity off the tennis ball using consideration off energy. Now, when the tennis ball went up by 515 meters hight, the change in the gravitational potential energy is mg hedge, mass being, let's say, the masses em times g times head And this energy comes from the kinetic energy off the body kind of energy off the tennis ball Here, here, the energy off the tennis balls completely candidate on. By the time it reaches the highest point, it is stationary and its energy is completely in the form of gravitational potential. Energy and start is equal to happen. We square. Hey, we can cancel the end and we know she hatches b squared by two. We know that she is 9.8 meters per second. Squared height is 5.5 meters on. We know that velocity is three square. That's it. Using this we can find is he called the square root off two times 515 times 9.8. This might remind you off the form Love you studied in the past week Old route, you idiot. No, this turns out to be 10.4 meters per second. No, because the artist is below stationary before the hit. We know that impulse is the change in momentum. Happy which means final moment on minus initial mourned him and we know that the initial momentum is zero because the object was stationary and the impulse is equal to the final moment. Um, which is simply mass times the velocity velocity being this velocity. Hence, this is 55 57 grams, which is 0.57 kilograms multiplied by and 0.4 meters per second. Therefore, the impulses 0.593 I need you for a second. I'm sorry, kid. You meet up for a second around where the Temple's has the units off momentum.

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