00:01
In this problem, we're told that q1 is equal to 3 times 107 -1 -negative 6 gullums, and q2 is that same value.
00:06
And so we can automatically tell that the force will be repulsive, since q1 and q2 share the same sign, right? they're both positive.
00:14
And we're also told that the distance between the two charges is equal to 0 .2 meters.
00:24
And so in order to figure out the magnitude of this repulsive force, we use f is equal to k times q1, q2 and absolute value signs over r squared.
00:36
And at this point, it's a simple plug -in chug.
00:39
So, k is equal to 8 .99 times 10 to the 9, and this is newton meters squared over kulam squared.
00:51
And we're multiplying this by q1, q2...