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$\bullet$ Two particles in a high-energy accelerator experiment areapproaching each other head-on, each with a speed of 0.9520$c$as measured in the laboratory. What is the magnitude of thevelocity of one particle relative to the other?

$$0.9988 c$$

Physics 101 Mechanics

Chapter 27

Relativity

Gravitation

University of Michigan - Ann Arbor

Hope College

University of Sheffield

McMaster University

Lectures

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all right. In this problem, we're told that two particles are approaching each other on each with a value of 0.9520 C as measured from the lab frame. So we'll use prime coordinates two to know the reference system attached a particle one which were also defining to be moving in the positive extraction. So in the lab frame, particle one has a velocity of positive 0.9520 C in particle, to which were associating with the velocity. U has well, save negative 0.9520 c. So if we want to transform to the lab frame of the first particle, then we use this formula and this is going to be 0.9520 C minus negatives. You're a 0.9520 c and this comes out too. 0.99 a. M A. C.

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