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$\bullet$ Two people carry a heavy electric motor by placing it on a light board 2.00 m long. One person lifts at one end with a force of $400.0 \mathrm{N},$ and the other lifts at the opposite end with a force of 600.0 $\mathrm{N}$ . (a) Start by making a free-body diagram of the motor. (b) What is the weight of the motor? (c) Where along the board is its center of gravity located?

a) see drawingb) 1.2 $\mathrm{m}$ from the left side

Physics 101 Mechanics

Chapter 10

Dynamics of Rotational Motion

Newton's Laws of Motion

Rotation of Rigid Bodies

Equilibrium and Elasticity

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straw, everybody Diagram of what's happening. Libbets. Traitor. We haven't access here and then go for party. We simply need to try the three bodies in the ground so and going straight up, we have a force of one on the other end. We have a force up to at the center of Mass. We have a weight and we know that the entire length of the beam is two meters and that this distance here well is considered X. So we can say that for part a toe, find the weight. We can say that for Party Sigma, some of forces in the UAE direction equals zero, and this equals force of one plus force up to minus the weight. Therefore, the weight is simply going to equal toe. What force of one plus force up to Ah, this will be equal to 400 plus 600 and the weight is found out to be 1,000 to Nunes. Now we're going to say that four sub one equals 400 Nunes and that's 600 Newtons equals force up to So for part B. When it's asking us for the center of mass, we can say the Sigma Tau equals zero and force up to times two meters is going to be equal, brother minus the wait. Times X is going to be equal to zero. So we can say that the axe is going to be equal to the force of two times two meters, divided by the weight. So this will be the force up to weaken, say, two times 600 divided by 1,000 and this is equal in 1.20 meters. So this would be the the distance of the center of mass. But again we have to specify from the Axis because we chose, um efs of one to be 400 Nunes. So we have to specify 1.20 meters from the axis would be the co ordinate for the center of mass. That is the end of the solution. Thank you for watching

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