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$\bullet$ Two point charges $Q$ and $+q$ (where $q$is positive) produce the net electric fieldshown at point $P$ in Figure $17.53 .$ The fieldpoints parallel to the line connecting thetwo charges. (a) What can you concludeabout the sign and magnitude of $Q ?$Explain your reasoning. (b) If the lowercharge were negative instead, would itbe possible for the field to have the direc-tion shown in the figure? Explain yourreasoning.

a) $Q$ is negativeb) $\mathrm{No}$ , it's not possible.

Physics 102 Electricity and Magnetism

Chapter 17

Electric Charge and Electric Field

Gauss's Law

Electric Potential

Cornell University

Simon Fraser University

University of Winnipeg

Lectures

11:53

In physics, a charge is a …

10:30

The electric force is a ph…

02:13

Two point charges $Q$ and …

07:45

05:30

Two charges are placed as …

03:34

The two charges $q_1$ and …

19:54

00:29

The figure above shows two…

03:33

The drawing shows a positi…

00:23

Charges $-q$ and $+2 q$ ar…

0:00

Two point charges of equal…

10:37

Two charges of equal magni…

03:48

09:06

Three equal positive charg…

05:04

Two charges, +Q and +2Q, a…

00:47

(a) Sketch the electric f…

02:17

Figure $P 15.94$ shows the…

05:37

02:01

CE The electric field line…

03:05

(a) Sketch the equipotenti…

05:18

Place two small electrical…

(a) Sketch the electric fi…

in this problem. We have something like this. We have a positive charge. Q. Directed dy down from this point p and we have another charge Q of unknown positive or negative nous. And it's Oppa Distance D from the pointy, and we know that the electorate fueled point sources. Capital Q. Now the key idea. This promise that the electric field points and the direction that a positive charge would go to. And so we're asked if this is possible and for what values of queues as possible. And there are two possibilities. The first is that he was positive. Some skin indicate that by that he was positive, and its magnitude is less thank you like that. So if Q's positive and it's bang, too, is less than little Q. Then this makes sense because even though there would be repelled here, there would be a small repel here than there is here. And so the electric field still be pointing up like that. The second option for this to work is Q. I would have to be negative, and it truly doesn't matter what's magnitude. This if Q is negative. Well, there will be repulsion force here and there will still be a Or there will be an attractive force here, and there will be repulsion here, and so evil still point in that direction. And so these are the two conditions. If one of them is satisfied that E can point in this direction and that completes party in Part B, we have a slightly different situation. The electric field is still pointing out. This is still Q. They're still the Q down here. Actually, it's native and the distance is the same. So still it still be there, and then do you hear? And so the question is, Is this still possible is their value and big Q. That makes the electric field still point up from this in the answer's yes, but in this case, there's only one way it can happen. And you would have to be so cue with half to be negative. And the magnitude of Q has to be greater than the mattered of little Q. Now this makes sense, because if Q is negative, then a positive charge sitting here would feel in attractiveness towards it. Now it also feeling attractiveness downward, and that's where the magnitude comes in If the attractiveness is still towards this pick you here than it will feel, the electric field will point destruction. But if mattered of queue is less than will queue, then it'll flip, and now little fuel and that attractiveness downward. And so this is the only condition that this could be possible in and like.

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