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$\bullet$ Unpolarized light with intensity $I_{0}$ is incident on an ideal polarizing filter. The emerging light strikes a second ideal polarizing filter whose axis is at $41.0^{\circ}$ to that of the first.Determine (a) the intensity of the beam after it has passed through the second polarizer and (b) its state of polarization.

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a) 0.285$I_{\circ}$b) linearly polarized

Physics 102 Electricity and Magnetism

Physics 103

Chapter 23

Electromagnetic Waves and Propagationof Light

Electromagnetic Waves

Reflection and Refraction of Light

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Lectures

02:30

In optics, ray optics is a geometric optics method that uses ray tracing to model the propagation of light through an optical system. As in all geometric optics methods, the ray optics model assumes that light travels in straight lines and that the index of refraction of the optical material remains constant throughout the system.

10:00

In optics, reflection is the change in direction of a wavefront at an interface between two different media so that the wavefront returns into the medium from which it originated. Common examples include the reflection of light, sound and water waves. The law of reflection says that for specular reflection the angle at which the wave is incident on the surface equals the angle at which it is reflected. Reflection may also be referred to as "mirror image" or "specular reflection". Refraction is the change in direction of a wave due to a change in its speed. The refractive index of a material is a measure of its ability to change the direction of a wave. A material with a higher refractive index will change the direction of a wave to a greater degree than a material with a lower refractive index. When a wave crosses the boundary between two materials with different refractive indices, part of the wave is refracted; that is, it changes direction. The ratio of the speeds of propagation of the two waves determines the angle of refraction, which is the angle between the direction of the incident and the refractive rays.

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Light of original intensit…

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$\bullet$ Light of origina…

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$\bullet$ A beam of unpola…

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A beam of unpolarized ligh…

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Three polarizing filters a…

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In the first part of this problem, we have to find the intensity of light after it has passed through the second horizon, so this density will be high. The density of light when it passes through the first polarizer is written, as i prime equals to 1 or 2 of i not where to. I notice the intensity of un polarized light and when the light passes through the second polarize. The intensity will be equals to. Prime cosine of cosine square of theta now inserting the value of i prime into the square we can write it is i equals to 1 or 2. I not and then cosine square of theta. We call this equation as equation. Number 1 point now: by inserting values into this equation, we can write, it is i equals to 1 over 2 and then we have the value for i not is i not and then cosine squared over theta is 41.0 degree, so this will give us a value For i s i equals to 0.285 of i not so this is the required answer. Well now, in part b of this problem, we have to talk about the state of polarization. The light is linearly polarized along the axis of second filter. End of the question.

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