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$\bullet$ You add 8950 J of heat to 3.00 mol of iron. (a) What is the temperature increase of the iron? (b) If this same amount of heat is added to 3.00 $\mathrm{kg}$ of iron, what is the iron's temperature increase? (c) Explain the difference in your results for parts (a) and (b).

a) $113.8 K=113.8^{\circ} C$b) $6.35 K=6.35^{\circ} C$c) The temperature change in part a is higher as in part a 3 moles contains less material than 3 kg of iron.Therefore, the less material will encounter high change in temperature due to the same amount of heat.

Physics 101 Mechanics

Chapter 14

Temperature and Heat

Thermal Properties of Matter

The First Law of Thermodynamics

University of Washington

Simon Fraser University

University of Winnipeg

Lectures

02:20

A solid, liquid, or gas is one of the three main states of matter. Solids have a definite shape and volume, and retain their shape when a force is applied to them. They are rigid, and do not flow to take on the shape of a container, but retain their own shape. Solids are held together by intermolecular forces, which are usually chemical bonds. Liquids have a free-flowing, continuous surface, and take the shape of a container. They flow to fill an available space. Their particles do not have a definite shape or volume, and they are not rigid. Gases have no definite shape or volume. They are not held together, and are not rigid. They flow to fill an available space. Gases are often described as being the state of matter with the lowest density.

03:25

The First Law of Thermodynamics is an expression of the principle of conservation of energy. The law states that the change in the internal energy of a closed system is equal to the amount of heat energy added to the system, minus the work done by the system on its surroundings. The total energy of a system can be subdivided and classified in various ways.

01:00

You add 8950 J of heat to …

05:50

I You add $5000 \mathrm{~J…

01:37

A 12.3-g sample of iron re…

02:03

Calculate the quantity of …

01:28

The specific heat of iron …

00:45

A $20.0-\mathrm{g}$ block …

Calculate the specific hea…

02:11

If 3.5 kJ of energy are ad…

Guys, let's take a look with the question. The question was asking us: the change in temperature and we know the heat is equal to mass and specific heat is the change in temperature, so the change in temperature is equal to q. Over mc heat is, the mass c is the specific heat, and in this question you was saying that there were 3 more irons in this question, and we know the molar mass of the question is 55.8 gram per mole, so the total mass will be 3 times. 58 means 55.8 gram per mole and that will give us 167.4 and if we converted to kilo, grains 0.1674 kilo, grains and the specific heat polar iron is 472 per kilbannon and the heat added to the aaron is 8950 jon. So now, let's work out our calculations. So we know that delta t delta t is equal to q over mc to a 950 joukery, see 8950 go over the mass, which is 0.1674 kilograms times the specific heat which is 472 over kilogram per kelvin, and that will give us the delta t is equal To 113.8 kelvin, okay, so that's the change in temperature for this question and as figure out changing temperature for the next question. So now the mass changed to 3 rest is the same and still looking for the changing temperature. So we know deltas equal to q over mc kay, so in this case is just simply equal to 8950 jou over m, which is 3 kilogram over c, which is 470 jou over kilogram times kelvin, and that will give us 6.35 kelvin wilts changing temperature carton c Was asking us to explain the difference of a result between a and b well, what is a huge difference between a and b c, the first 1 was 113.8 kelvin, and the second 1 was having a change in temperature of 6.35 kelvin y s. Well, let's take a look at the formula here. You see, q is equal to mc delta. T so delta t is equal to q. Over mc q is constant because from the question c, never change c. Never change. Okay and c is the subtile. Basically, doesn't change and q was always 8952 point, so that means only the mass and the temperature is changing and we can tell the first 1 was composed of 3 mole molar mass and the second 1 was given at 3 kilograms. So you see i squared the c and c as a constant. So the mentality is only related to 1 over n and is negatively correlated y set. Because if you increase the value of m, the delta t will decrease and if you decrease the value of m, the delta t will increase. And that's why the change in temperature. For the first question was huge because the mass of the arato equation was a smaller than the mass in the question 2. Okay and that's my explanation for this question. Thank you.

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