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$\bullet$$\bullet$ A person pushes on astationary 125 N box with75 $\mathrm{N}$ at $30^{\circ}$ below the hori-zontal, as shown in Fig-ure 5.56 . The coefficient ofstatic friction between thebox and the horizontal flooris 0.80 . (a) Make a free-body diagram of the box. (b) What is the normal force on thebox? (c) What is the friction force on the box? (d) What is thelargest the friction force could be? (e) The person now replaces thehis push with a 75 $\mathrm{N}$ pull at $30^{\circ}$ above the horizontal. Find thenormal force on the box in this case.

a) 4.05 $\mathrm{m} / \mathrm{s}^{2}$b) 162.5 $\mathrm{N}$c) 130 $\mathrm{N}$ d) 160 $\mathrm{N}$e) 87.5 $\mathrm{N}$

Physics 101 Mechanics

Chapter 5

Applications of Newton's Law

Motion Along a Straight Line

Motion in 2d or 3d

Newton's Laws of Motion

Applying Newton's Laws

Cornell University

Hope College

University of Sheffield

Lectures

04:01

2D kinematics is the study…

03:28

Newton's Laws of Moti…

02:28

A box full of books rests …

02:07

A 2.0 -migh box with a 1.0…

10:05

A 2.0-m-high box with a 1.…

04:34

Boxes $A$ and $B$ are in c…

02:25

(II) A small box is held i…

03:37

A 50 -kg box rests on the …

04:29

$\bullet$$\bullet$ You pus…

05:20

You are lowering two boxes…

05:29

04:41

A 5.0-kg box rests on a ho…

02:24

A 1.5 $\mathrm{kg}$ box is…

08:55

04:59

A 40.0 -kg box initially a…

0:00

02:20

(I) A force of 48.0 $\math…

04:28

Two boxes connected by a l…

02:15

A box with a mass of 10 $\…

03:49

A box is dragged across th…

04:23

A box with mass 10.0 kg mo…

06:55

the free body diagram for this part is shown here. No force acting upwards, crabbed, inciting downwards. And then you have the applied force the Porsche, which we're calling p exacting at an angle 30 degrees from the horizontal. So this is the angle and and said And so you have a fictional force just opposing the motion of defecting to the right. So to start party, it's decompose thiss pushing for us and do its vertical and horizontal components. Say you have do any degree angle here and this is P. So the horizontal component she's hacking in the negative wax exact system. This thinking of extraction, this case is P CO sign 30 and the vertical component the negative. Why Axis is P sign 30. Okay, so this is to set up and what this means is out. We can resolve forces in the white direction, which will be zero. This would lead to end in the up upward for a put force. The core energy, uh, gravity, plus the white component P signed 30 like a part of the pushing force on dso MGs. Just 1 25 1 25 your months and pia 75 And so we get normal for us of 1 63 news. Okay, Excellent on part. See, Similarly similar to part B. The result forces the extraction. And and again, there's no there's no net force. And so we have f ah, which is a frictional forces. He called to Pete in the horizontal component pushing force of Pecos 30. And so this s o. This is 75 coast 30. So are you frictional Force 65 needs party. Um, you have a party. You have no, um, use of ass that is given and we know end. So you're frictional force. Your fictional force will be well, some simply be are your static friction force will simply be mischievous times and the normal force. And so mischievous is 0.8 normal force this 1 63 as we found in part B. So this comes out to one thirteen 13 and finally part E In partly, you have the same everybody diagram, but one adjustment, which is r. Well, I guess it would be a couple of adjustments here. But the main difference here is that this is a pulling force now P is acting. Ah is acting to the diagonal, right? And so the affection would be to the left, too. So in this case, you still in the still of the same angle on everything but the vertical component of pea Eye's acting up words this time. And the horizontal compartment P is acting to the right this time. So, um so this is Sparky. So we resolve forces in the white direction. And again, that is, there is no Net Force, sir. And so you have n plus p sign 30 This time equals and she and so and is just em xi minus pew. Sign 30. So that's 1 25 minus 75 70 30 which gives us 88 newts in this case.

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