Question
$\bullet$$\bullet$ A plane sinusoidal electromagnetic wave in air has a wave-length of 3.84 $\mathrm{cm}$ and an $\vec{\boldsymbol{E}}$ field amplitude of 1.35 $\mathrm{V} / \mathrm{m}$ .(a) What is the frequency of the wave? (b) What is the $\vec{\boldsymbol{B}}$ field amplitude? (c) What is the intensity? (d) What average force does this radiation exert perpendicular to its direction of propagation on a totally absorbing surface with area 0.240 $\mathrm{m}^{2}$ ?
Step 1
Substituting the given values, we get $f = \frac{3.00 \times 10^{8} \, \text{m/s}}{3.84 \times 10^{-2} \, \text{m}} = 7.81 \times 10^{9} \, \text{Hz}$. Show more…
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A plane sinusoidal electromagnetic wave in air has a wavelength of $3.84 \mathrm{~cm}$ and an $\vec{E}$ -field amplitude of $1.35 \mathrm{~V} / \mathrm{m}$. (a) What is the frequency of the wave? (b) What is the $\vec{B}$ -field amplitude? (c) What is the intensity? (d) What average force does this radiation exert perpendicular to its direction of propagation on a totally absorbing surface with area $0.240 \mathrm{~m}^{2} ?$
A plane sinusoidal clectromagnetic wave in air has a wavelength of 3.84 $\mathrm{cm}$ and an $\overrightarrow{\boldsymbol{E}}$ -field amplitude of 1.35 $\mathrm{V} / \mathrm{m}$ . (a) What is the frequency? (b) What is the $\overrightarrow{\boldsymbol{B}}$ -field amplitude? (c) What is the intensity?(d) What average force does this radiation exert on a totally absorbing surface with area 0.240 $\mathrm{m}^{2}$ perpendicular to the direction of propagation?
A plane sinusoidal electromagnetic wave in air has a wavelength of 3.84$\mathrm { cm }$ and an $\vec { \boldsymbol { E } }$ -field amplitude of 1.35$\mathrm { V } / \mathrm { m }$ . (a) What is the frequency? (b) What is the $\vec { \boldsymbol { B } }$ -field amplitude? (c) What is the intensity? (d) What average force does this radiation exert on a totally absorbing surface with area 0.240$\mathrm { m } ^ { 2 }$ perpendicular to the direction of propagation?
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