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$\bullet$$\bullet$ A point charge of $-4.00 \mathrm{nC}$ is at the origin, and a secondpoint charge of $+6.00 \mathrm{nC}$ is on the $x$ axis at $x=0.800 \mathrm{m}$ . Findthe magnitude and direction of the electric field at eachof the following points on the $x$ axis: (a) $x=20.0 \mathrm{cm}$ ,(b) $x=1.20 \mathrm{m},(\mathrm{c}) x=-20.0 \mathrm{cm} .$

a) $E=1048.555 N / C \rightarrow$ in the negative $\mathrm{x}$ directionb) $E=312 N / C \rightarrow$ in the positive $x$ directionc) $E=844.83 N / C \rightarrow$ in the positive $\mathrm{x}$ direction

Physics 102 Electricity and Magnetism

Chapter 17

Electric Charge and Electric Field

Gauss's Law

Electric Potential

Cornell University

University of Michigan - Ann Arbor

University of Sheffield

McMaster University

Lectures

13:02

In physics, potential ener…

18:38

In physics, electric flux …

06:05

$\bullet$$\bullet$ A charg…

02:33

$\bullet$$\bullet$ Two poi…

06:03

Two point charges lie on t…

10:10

07:12

$\bullet$$\bullet$ Three p…

03:29

A point charge $q_1 = -$4.…

12:20

$\bullet$ In a rectangular…

07:04

The electric field at the …

0:00

In a rectangular coordinat…

04:30

Two point charges are on t…

03:27

Point charge $q_1 = -$5.00…

06:58

Two $2.00-\mu \mathrm{C}$ …

07:28

A $65-\mu \mathrm{C}$ poin…

14:59

(III) $\mathrm { An } 8.00…

04:39

A very long uniform line o…

08:43

$A+2.00-n C \quad$ point c…

04:46

$\bullet$$\bullet \mathrm{…

02:29

A uniform electric field o…

03:13

The two charges in Figure …

04:41

problem number 41. It is given that there are no charges wanted. The origin minus for Nana columns and the other at 0.8 meters, which is blood. Six Nana columns and we have to pull. Find the net electric field at Point A, which is at 0.2 meters from the origin. Now we know that the electric field, due to the positive charges points of it from the poster child. So electric field to do plus six Nana columns is in the left direction and the electric field, due to negative charges, always point towards the charge. So the electric field at point A due to the minus for Nana collapses also towards the left. So the net electric field at the point a to do the two charges is towards the left only you two ex direction. So we can write the net electric field at the point a as e here because to nine into 10 to the power night which is equal to columns constant Indo six into 10 to the power minus name bye zero point 60 square plus pour into 10 to the power minus nine into nine into 10 to the power minus name nine upon zero point Do we square. This will give us the net electric field at point A as 1050 new temper columns, the words minus ex direction in the party. The charges remain same, but we have to find out that electrical at one p which is that 1.2 meters from the origin. The other two charges remain same minus four. They're no columns. And last six Nana columns, which is that gear? Open it meters. We know that electric will point our courts from the positive charge. So do do. Plus 600 columns Ella took Will is in the right direction. And due to the minus for Nana columns, electric field is in the left direction. So the net electric field at point we can will. It s e v equals nine into 10 to the power nine indu six into tended a power minus nine upon one going toe minus 0.8 bullets square minus nine into 10 to the power nine into four into 10 to the power minus nine upon 1.2 only square. We know that electric field formula is equal Okay, You. Why rd squared? There are is their distance from the judge. So not electric field at one b is equal. Do 312.5 new temper columns in the last six direction in the Parsi, it is us that not electric field at one see, which is minus zero point no meters and other do judges are saying minus born and no columns. That's 69 of problems. So at one c, we can right that not electric field E. C. As the electric field to do what Steve Child is in left direction and the electrical you too. Negative charges towards the *** to chance in right direction. So the net electric pillar The point. Seek and bitterness nine into 10 to the power nine into six into 10 to the power minus name. Bye zero point it plus 0.2 square minus nine into 10 to the power nine into four into 10 to the power minus name. Bye 0.2 Esquire. On solving this, we will get 8 46 Newton Bar Ghoulam's in the less X direction

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