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$\bullet$$\bullet$ Force on a tennis ball. The record speed for a tennis ballthat is served is 73.14 $\mathrm{m} / \mathrm{s}$ . During a serve, the ball typicallystarts from rest and is in contact with the tennis racquet for30 $\mathrm{ms}$ . Assuming constant acceleration, what was the averageforce exerted on the tennis ball during this record serve,expressed in terms of the ball's weight $W ?$

$F=250 W$

Physics 101 Mechanics

Chapter 5

Applications of Newton's Law

Motion Along a Straight Line

Motion in 2d or 3d

Newton's Laws of Motion

Applying Newton's Laws

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question 19. It seems that the record speed for a tennis ball that has served is 73.14 meters per second. During a serve, the bolt typically starts from rest and is in contact with the tennis racket for 30 milliseconds. Assuming constant acceleration. What was the average force exerted on the tennis bowl during this record? Serve expressed in terms of the bulls weight W These aren't givens here. Um, well, this should be zero. Sorry. We assume that in the scenario, uh, industry from rest started, you want to do anything Initial velocity of the ball zero we do the final velocity to be 73.14 mills, 14 million meters per second. Excuse me, two basic givens. If we think back to our kinetic equations, we can use the following expression to solve for the acceleration of the bowl. In this time frame, we have our final velocity, their initial velocity, plastic celebration. Time to time. We're told that that initial lossy is zero sitting insult for acceleration to be velocity over time, playing our values at 73.14 meters per second, divided by 30 milliseconds, Bush of course, of course, needs to be converted two seconds. We divide that by 1000 when you find the acceleration in this time frame is a very large value of 2438 meters per second squared and my given this expression more value for acceleration. You know, of course, Thea Force exerted on it isn't the mass times acceleration were not given us and the problem. But we know that the race ship, the masses just the wheat or G one way by value for a So we know G and you know, a But we're well don't know you. But I want express your answer in terms of W anyway to be taking value from a found in the first part of this question. Divide that by 9.8 Fergie and we find on our value for the wait. All right, but these in terms of weight is to 48.8 times w Looking back really want to see a few years? So it means we can simply represent our final answer of the force exerted on the ball to be 250 times its weight

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