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$\bullet$$\bullet$ If the central charge shown in Figure 17.46 is dis-placed 0.350 nm to the right while the other charges areheld in place, find the magnitude and direction of the netforce that the other two charges exert on it.

$4.282 \times 10^{-10} N$ to the left

Physics 102 Electricity and Magnetism

Chapter 17

Electric Charge and Electric Field

Gauss's Law

Electric Potential

Hope College

University of Sheffield

University of Winnipeg

McMaster University

Lectures

11:53

In physics, a charge is a …

10:30

The electric force is a ph…

07:55

(II) Particles of charge +…

06:12

(II) Particles of charge $…

03:23

01:17

Two identical charges are …

05:16

Two point charges are loca…

05:26

$\bullet$$\bullet$ Two poi…

01:30

$\bullet$ Two equal point …

16:01

(II) Two negative and two …

01:28

In the figure above, four …

02:09

04:35

$\bullet$ $\bullet$ Three …

01:43

Two point charges are plac…

07:24

Calculate the magnitude an…

01:44

A positive charge of $3.0 …

09:06

Find the direction and…

06:02

Three negative point charg…

02:22

Two very long uniform line…

0:00

Three charges are arranged…

15:55

Two charges $+3 \mu \mathr…

02:25

problem number 27. In this problem, it is given that there are three charges that's too easy, less to eat, less to eat. And they have initially distances one point five centimeters between them. But when the middle charge is shifted towards right by our distance, 0.3 50 nano meters X is going to 0.350 nano meters. Then the new separation between that charges becomes one point 85 nano meter. And between these two charges, the new suppression becomes 1.15 nano meters. No, we know that when the distance between two charges decreases, then the force between them increases like this force we, everyone and this force me after two, then have one will be greater than I have to, because distance between these two charges is big freezing, so force between them increases so net force on them. A little charge is written as ethical to F one minus. I have to no writing the formulas. Okay, Indu for e squared upon distance between that two charges which is one point 15 into 10 to the power minus nine, he squared minus after force, which is gay for E Square bye, one point 85 into 10 to the power minus nine square. Now, substituting the values we get cares the Coolum constant and it has value off nine into 10 to the power nine into four is the charge off one electron, which is 1.6 into 10 to the power minus 19 squared bye, 1.15 into 10 to the power minus nine square. This is the 47 minus nine into 10 to the power nine into four into 1.6 into 10 to the power minus 19. It's square upon 1.85 into 10 to the power minus time square. Now solving this, we get 69 wine 68 into 10 to the power minus 11 minus 26.93 into Pento, the power minus 11. This will give us 42 0.75 into 10 to the power minus 11 which is equal to 4.27 into 10 to the power minus, then new tons. This is the net force on the middle child. When that distances between the charges is chased

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