Problem

$\bullet$$\bullet$ Two point charges are located…

05:26

Question

Answered step-by-step

Problem 20 Medium Difficulty

$\bullet$$\bullet$ If two electrons are each
$1.50 \times 10^{-10} \mathrm{m}$ from a proton,
as shown in Figure $17.41,$ find
the magnitude and direction of
the net electrical force they will
exert on the proton.

Video Answer

Solved by verified expert

Textbook Answer

Official textbook answer

Video by Ryan Hood

Numerade Educator

This textbook answer is only visible when subscribed! Please subscribe to view the answer

Related Courses

Physics 102 Electricity and Magnetism

College Physics

Chapter 17

Electric Charge and Electric Field

Discussion

You must be signed in to discuss.

Top Physics 102 Electricity and Magnetism Educators

Christina Krawiec

Rutgers, The State University of New Jersey

Watch More Solved Questions in Chapter 17

Problem 1

Problem 2

Problem 3

Problem 4

Problem 5

Problem 6

Problem 7

Problem 8

Problem 9

Problem 10

Problem 11

Problem 12

Problem 13

Problem 14

Problem 15

Problem 16

Problem 17

Problem 18

Problem 19

Problem 20

Problem 21

Problem 22

Problem 23

Problem 24

Problem 25

Problem 26

Problem 27

Problem 28

Problem 29

Problem 30

Problem 31

Problem 32

Problem 33

Problem 34

Problem 35

Problem 36

Problem 37

Problem 38

Problem 39

Problem 40

Problem 41

Problem 42

Problem 43

Problem 44

Problem 45

Problem 46

Problem 47

Problem 48

Problem 49

Problem 50

Problem 51

Problem 52

Problem 53

Problem 54

Problem 55

Problem 56

Problem 57

Problem 58

Problem 59

Problem 60

Problem 61

Problem 62

Problem 63

Problem 64

Problem 65

Problem 66

Problem 67

Problem 68

Problem 69

Problem 70

Problem 71

Problem 72

Problem 73

Problem 74

Problem 75

Problem 76

Problem 77

Problem 78

Problem 79

Video Transcript

and this problem. We want to figure out the net force on this positive charges. And so we have a Force F one pulling it to the right, and we have a force of two pulling it up at an angle 65 degrees. With respect to the war zone, these two forces will be the same in magnitude, since the charges on the end of each will be the same and then the distance our is also the same between them. So let's calculate that magnitude. So F one is equal to have to just the magnitudes here and it's equal to K Time's Q on Q too over R squared. Well, this is just equal to K e squared, since both charges here have absolutely charge he for our school. And now he is known constant casing on constant ours, given in the problem. So we can solve this to get 1.23 times 10 to the negative eight noons. Now that we know that we need to break up each of these forces into its X and Y components where the X in my directions are shown here and so let's go ahead and bring down this 1st 1 F one, which is this horizontal force here in the extraction is just equal to the full force. Since it's fully pointing in the extraction. This's 1.23 times 10 to the negative eight News and F one Why? Which is like 10 nunes F two x, which is this guy is going to have non zero x and Y components and scum. You're related to the angle here. And so I have to Axe is equal to have to times go sign 65 degrees because that is the horizontal component. And this is, uh, being 4.32 times 10 to the negative nine noons and F two. Why is just equal tio two times signe of 65 degrees. And so this is equal to 9.2 son times 10 to the negative nine Nunes. And now I can add the ex components about these forces to get the result into X component. And so FX is able to f one x plus after Max and these are on the page and I just uris this one here. So these two numbers here combined to give 1.46 times 10 to the negative eight noons now. Similarly, if y is equal to F one lie, let's have two. Why? And adding These, too gives 9.27 time stands the name nine new ones. The resultant Magnitude Force F is equal to squared of FX squared plus F y squared. And when we play the same, we should get our original left that we found in the problem. And so playing this in, we get 1.73 times 10 to the negative eight noons. So this is the magnitude of the resultant force from both F one and 1/2 to and so figure out the angle that's directed. And we can say that the tangent of data is equal to that fly over FX, and we know f flying effects. They're just here and so feeling those in give 0.6349 and then taking the inverse tangent will give us the angle so theta is equal to 32.4 degrees, so the resultant force will have magnitude. This and we'll be angled at 32.4 degrees with respect to the horizontal, and that completes the answer

Get More Help with this Textbook

Hugh D. Young

College Physics

View More Answers From This Book

Find Another Textbook

Study Groups

Study with other students and unlock Numerade solutions for free.

Problem

$\bullet$$\bullet$ Two point charges are located…