00:01
In this problem, we are going to calculate the largest value of this alpha, which can satisfy the given condition.
00:07
So we need to find this alpha.
00:10
In order to calculate this alpha, let me apply the snals -ride interface, glass air interface.
00:17
So we can write ng sine theta, sine alpha -c equals to n -a sine 90 degree.
00:31
As for the largest value of alpha, this should be critical angle, so the refractive angle will be 90 degree.
00:39
So from here we can calculate this alpha c as alpha c equals to sine inverse of n, a, divided by ng, and then there will be 1, which is equals to 90, sine 90 degree...