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$\bullet$$\bullet$ Resolution of the eye, I. Even if the lenses of our eyesfunctioned perfectly, our vision would still be limited due todiffraction of light at the pupil. Using Rayleigh's criterion,what is the smallest object a person can see clearly at his nearpoint of 25.0 $\mathrm{cm}$ with a pupil 2.00 $\mathrm{mm}$ in diameter and light ofwavelength 550 $\mathrm{nm}$ ? (To get a reasonable estimate withouthaving to go through complicated calculations, we'll ignorethe effect of the fluid in the eye.) Based upon your answer,does it seem that diffraction plays a significant role in limitingour visual acuity?

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0.084 mmNoOur eye can resolve a small size, even less than 0.084 mm, at the near point; therefore, diffraction does not play a significant role in limiting our visual acuity.

Physics 102 Electricity and Magnetism

Physics 103

Chapter 26

Interference and Diffraction

Electromagnetic Waves

Reflection and Refraction of Light

Rutgers, The State University of New Jersey

Hope College

University of Winnipeg

Lectures

02:30

In optics, ray optics is a geometric optics method that uses ray tracing to model the propagation of light through an optical system. As in all geometric optics methods, the ray optics model assumes that light travels in straight lines and that the index of refraction of the optical material remains constant throughout the system.

10:00

In optics, reflection is the change in direction of a wavefront at an interface between two different media so that the wavefront returns into the medium from which it originated. Common examples include the reflection of light, sound and water waves. The law of reflection says that for specular reflection the angle at which the wave is incident on the surface equals the angle at which it is reflected. Reflection may also be referred to as "mirror image" or "specular reflection". Refraction is the change in direction of a wave due to a change in its speed. The refractive index of a material is a measure of its ability to change the direction of a wave. A material with a higher refractive index will change the direction of a wave to a greater degree than a material with a lower refractive index. When a wave crosses the boundary between two materials with different refractive indices, part of the wave is refracted; that is, it changes direction. The ratio of the speeds of propagation of the two waves determines the angle of refraction, which is the angle between the direction of the incident and the refractive rays.

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Even if the lenses of our …

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Resolution of the Eye. The…

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in this problem. We are looking at the resolution angle of the eye and seeing if diffraction please Ah, significant role in how is see objects. So assuming that our field of vision was a distance of 25 centimeters away on the diameter of our people, it was two millimeters with a wavelength of light at 550 nanometers. What is the maximum? Various? The minimum size that we can see. So are really angle given by 1.22 Lambda over D And as with most of our really problems, we can assume that our angle is approximately. Why, over s because the size of the object is going to be smaller than the distance that we're observing it up. So if we put these two things together, me at 1.2 to Lambda over D is equal to why Over S and we want to solve for y because that's gonna be the size of the object that we're looking at. So 1.2 to Landover de multiplying by s to the other side saying at 1.22 Landa was 550 nano tend to the negative nine meters D is two times 10 to the negative three Millie meters and us is 25 senti so 10 to the negative, two liters. So if I played that into my calculator, I get 83.9 micro meters, which is really small.

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