Question
$\bullet\bullet$ The equation of motion of a particle in vertical SHM is given by $y=(10 \mathrm{~cm}) \sin [(0.50 \mathrm{rad} / \mathrm{s}) t]$. What are the particle's(a) displacement(b) velocity, and (c) acceleration at $t=1.0 \mathrm{~s}$ ?
Step 1
50 \mathrm{~rad} / \mathrm{s}) t]$. We need to find the displacement of the particle at $t=1.0 \mathrm{~s}$. We can substitute $t=1.0 \mathrm{~s}$ into the equation to find the displacement. \[ y=(10 \mathrm{~cm}) \sin [(0.50 \mathrm{~rad} / \mathrm{s}) (1.0 Show more…
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