Problem

$\bullet$$\bullet$ Two small spheres spaced 20.0 …

02:24

Problem 15 Medium Difficulty

$\bullet$$\bullet$ Two small aluminum spheres, each having mass 0.0250 $\mathrm{kg}$ ,
are separated by 80.0 $\mathrm{cm}$ . (a) How many electrons does each
sphere contain? (The atomic mass of aluminum is 26.982 $\mathrm{g} / \mathrm{mol}$ ,
and its atomic number is $13 .$ (b) How many electrons would
have to be removed from one sphere and added to the other to
cause an attractive force between the spheres of magnitude
$1.00 \times 10^{4} \mathrm{N}$ (roughly 1 ton)? Assume that the spheres may
be treated as point charges. (c) What fraction of all the elec-
trons in each sphere does this represent?

Answer

a) $7.254 \times 10^{24}$ electrons
b) $=7.26 \times 10^{-10}$

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Physics 102 Electricity and Magnetism

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Chapter 17

Electric Charge and Electric Field

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Abul R.

April 7, 2022

Two small aluminum spheres, each having mass 0.0250 kg, are separated by 80.0 cm. (a) How many electrons does each sphere contain? (The atomic mass of aluminum is 26.982 gmol, and its atomic number is 13.) (b) How many electrons would have to be removed f

Abul R.

April 7, 2022

Abul R.

April 7, 2022

Abul R.

April 7, 2022

Abul R.

April 7, 2022

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Video Transcript

problem number 15. In this problem, it is given That too is fears are there having must 0.0 250 kg and they are separated by zero point did meters. The agreement must off aluminium. He's given us 26.9 it to Gramps. But morning off phantoms, so we can write one Graham aluminium. This she could learn toe one mall bye. 26.982 atoms So total months off each is fear which is 0.250 Yeah, G off aluminium is equal in tow. 0.250 into 10 to the power three by 26.982 morn atoms and we know that each atom one Adam has her demon electrons when they come is neutral then attempts in 0.25 kg is fear will be total electrons in this fear is equal to total number of atoms in tow. Electron my rectum, you're done Atoms in tow Electron Adam Hotel A. Tim's we have already calculated for each is fear, which is 0.250 in tow, 10 to the power three into one mole upon 26 points. 982 Indo. And we know that one mole is equal to six into 10 to the power 23 atoms. So V for its value Indo six into 10 to the Power Dante three into tartine upon on this six point 982 This will give us the total number off electrons. T isa Carlito. So indeed to fine. 27 into 10 to the power 23 electrons. This is the required answer for party now in part, be off the question we are given that dark force between don't His fears is tend to the power for Newton's and electrons are transferred from one is fear to other. Give them a charge. Q. Now we have to find that neck charged on each is fear. We will do this by employing electrostatic force formula, which is total force is equal to columns, constant in tow charge or needs this fear into charge on and others fear upon this change between them. This will give us now charge on each is rear q equals two 8.4 great toe into 10 to the power minus four hoodlums Now to find out the number off electrons. New do, which is for years have acquired discharge the number off electrons and equal to total charge on each is fear divided by charge off one electron. This will give us any calls, too. 51 27 in tow. Pento the power 15 electrons. Now, in the third part of the question, we have to find the fraction off electrons on charges. Fear do. The total number off electrons present in the is fear in party that acquired fraction is then upon P is equal to 5.27 in to tend to the powers 15 upon. So tell them what off electrons, which we have already find in our day. This figure was that acquired a fraction as 72 19 into 10 to the power minus 11. This is the required answer.

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