00:01
In this problem, we're standing at a height of 1 .75 meters, or at least our eyes are at the height, above the edge of a pool here.
00:09
Now, we're told that we're barely able to see the object in the pool.
00:14
And so we're going to have a refraction at the corner of the pool.
00:18
We know we're going to be looking at the corner because we're just barely able to see the object.
00:24
The depth of the water is 2 .5 meters below the corner, and the distance horizontally of our eyes from the corner is 2 meters.
00:31
We want to figure out the horizontal distance from the corner of the pool or the edge of the pool to the object.
00:40
And so first, let's figure out what this theta t is by using some geometry.
00:46
We know that tangent of theta t is equal to the opposite over the adjacent, which is 2 over 1 .75.
00:56
And so this tells us that theta t, if you take the inverse tangent, is 48 .81...