At 25 degrees Celsius, $\mathrm{pK}_{w}$ is equal to 14. We are given that the $\mathrm{pK}_{a}$ of butyric acid is 4.84. We can substitute these values into the equation to solve for $\mathrm{pK}_{b}$:
\[4.84 + \mathrm{pK}_{b} = 14\]
Solving for $\mathrm{pK}_{b}$
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