00:01
For this question, we're told that butyric acid has one ionizable hydrogen.
00:09
So we're going to give it the chemical formula hx to start with our balanced equation.
00:18
So hx will react with an a .o .h to produce an ax and h2o.
00:26
And we'd hold that 1 .187 gram of the butyric acid will react with 0 .5132 molar, 26 .28 milliliters sodium hydroxide.
00:46
So for part a, what is the molecular weight of the butyric acid? so we'll find the moles of sodium hydroxide, which would be equal to the malarity times the volume.
01:00
Convert it to liters.
01:03
This gives us 0 .0135 moles of the sodium hydroxide.
01:15
Now using our reaction stoichiometry, one mole of sodium hydroxide, react with one mole of butyric acid, hx.
01:31
This gives us 0 .135 moles of the hx...