Question
By directly substituting the values of the fundamental constants, show that the ground state energy for hydrogen in the Bohr model $E_{1}=-m_{\mathrm{e}} k^{2} e^{4} /\left(2 \hbar^{2}\right)$ has the nu- $-$ merical value $-13.6 \mathrm{eV}$.
Step 1
The equation is given as $E_{1}=-m_{\mathrm{e}} k^{2} e^{4} /\left(2 \hbar^{2}\right)$. Show more…
Show all steps
Your feedback will help us improve your experience
Narayan Hari and 72 other Physics 103 educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
By directly substituting the values of the fundamental constants, show that the ground state energy for hydrogen in the Bohr model $E_{1}=-m_{\mathrm{e}} k^{2} e^{4} /\left(2 \hbar^{2}\right)$ has the numerical value -13.6 eV.
By directly substituting the values of the fundamental constants, show that the Bohr radius $a_{0}=\hbar^{2} /\left(m_{\mathrm{e}} k e^{2}\right)$ has the numerical value $5.29 \times 10^{-11} \mathrm{m}.$
Show, by actual calculation, that the Bohr radius is $0.0529 \mathrm{nm}$ and that the ground-state energy of hydrogen is $-13.60 \mathrm{eV}$
Transcript
Watch the video solution with this free unlock.
EMAIL
PASSWORD