00:01
Hi there, so for this problem, we are told that by drawing analogies between the column force law and the gravitational force, we need to use the equation 6 .8 for the deflection in rooted for scattering to obtain equation 15 .22 for the deflection of photons.
00:20
And we need to assume that the photon behaves as it has mass, where the mass is equal to the energy divided by, the speed of light to the square.
00:37
So we will have two equations in here.
00:40
We will have the colon force, which is equal to the product between two electrons, the quantities for the charges of two electrons, over two, four times, pi times, epsilon sub -0.
00:59
And these times, we're going to call this, seta times the atomic number divided by the separation to the square.
01:15
On the other hand, we will have the gravitational constant, which is equal to the gravitational force, which is the gravitational constant times the mass, times the mass capital m divided by the separation between those two masses.
01:34
So we can change expressions based on the column force into those based on the gravitational force by just replacing this term by this term, as you can see.
02:05
So equation 6 .a then becomes the following.
02:09
So we will think that b is equal to cta times beta, k...