By integrating the binomial expansion, prove that, for a positive integer $n$,
$$
1+\frac{1}{2}\left(\begin{array}{l}
n \\
1
\end{array}\right)+\frac{1}{3}\left(\begin{array}{l}
n \\
2
\end{array}\right)+\cdots+\frac{1}{n+1}\left(\begin{array}{l}
n \\
n
\end{array}\right)=\frac{2^{n+1}-1}{n+1}
$$.